命名类型 [com.go_task.entity.User@5b4d25e7] 未实现 BasicType 也未实现 UserType

huangapple
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英文:

Named type [com.go_task.entity.User@5b4d25e7] did not implement BasicType nor UserType

问题

以下是翻译好的代码部分：

User.java

  1. package com.go_task.entity;
  3. import javax.persistence.*;
  4. import java.io.Serializable;
  5. import java.util.ArrayList;
  6. import java.util.List;
  8. @Entity
  9. @Table(name = "users")
  10. public class User implements Serializable {
  12.     @Id
  13.     @GeneratedValue
  14.     private int id;
  16.     @Column(name = "name")
  17.     private String name;
  19.     @Column(name = "email")
  20.     private String email;
  22.     @Column(name = "password")
  23.     private String password;
  25.     @OneToMany(mappedBy = "user", cascade = CascadeType.ALL)
  26.     private List<Task> tasks = new ArrayList<>();
  28.     // 构造函数和 getter、setter 方法
  30.     // ...
  31. }

Task.java

  1. package com.go_task.entity;
  3. import javax.persistence.*;
  4. import java.io.Serializable;
  6. @Entity
  7. @Table(name = "tasks")
  8. public class Task implements Serializable {
  10.     @Id
  11.     @GeneratedValue
  12.     private int id;
  14.     @Column(name = "title")
  15.     private String title;
  17.     @ManyToOne
  18.     private User user;
  20.     // 构造函数和 getter、setter 方法
  22.     // ...
  23. }

HibernateUtil.java class

  1. package com.go_task.database;
  3. import com.go_task.entity.Task;
  4. import com.go_task.entity.User;
  5. import org.hibernate.SessionFactory;
  6. import org.hibernate.boot.registry.StandardServiceRegistryBuilder;
  7. import org.hibernate.cfg.Configuration;
  8. import org.hibernate.service.ServiceRegistry;
  10. public class HibernateUtil {
  12.     private static SessionFactory sessionFactory = null;
  14.     public static SessionFactory getSessionFactory() {
  15.         if (sessionFactory == null) {
  16.             try {
  17.                 Configuration configuration = new Configuration();
  18.                 configuration.configure("db/hibernate.cfg.xml");
  19.                 configuration.addAnnotatedClass(User.class).addAnnotatedClass(Task.class);
  21.                 ServiceRegistry serviceRegistry = new StandardServiceRegistryBuilder()
  22.                         .applySettings(configuration.getProperties()).build();
  23.                 sessionFactory = configuration.buildSessionFactory(serviceRegistry);
  24.                 return sessionFactory;
  26.             } catch (Exception e) {
  27.                 e.printStackTrace();
  28.             }
  29.         }
  30.         return sessionFactory;
  31.     }
  32. }

Test.java

  1. package com.go_task.dao;
  3. import com.go_task.database.HibernateUtil;
  4. import com.go_task.entity.User;
  5. import org.hibernate.Session;
  6. import org.hibernate.Transaction;
  8. public class Test {
  10.     public static void main(String[] args) {
  11.         User user1 = new User("Name", "email", "pass");
  13.         Transaction transaction = null;
  15.         try (Session session = HibernateUtil.getSessionFactory().openSession()) {
  16.             transaction = session.beginTransaction();
  17.             session.save(user1);
  18.             transaction.commit();
  19.         } catch (Exception exception) {
  20.             if (transaction != null) transaction.rollback();
  21.             exception.printStackTrace();
  22.         }
  23.     }
  24. }

hibernate.cfg.xml

  1. <?xml version="1.0" encoding="utf-8"?>
  2. <!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
  3. <hibernate-configuration>
  4.     <session-factory>
  5.         <!-- Hibernate 配置信息 -->
  7.         <!-- ... -->
  8.     </session-factory>
  9. </hibernate-configuration>

当我尝试运行Test.java类时，出现了下面的异常：

  1. java.lang.IllegalArgumentException: Named type [com.go_task.entity.User@5b4d25e7] did not implement BasicType nor UserType
  2. 	at org.hibernate.boot.model.TypeDefinition.createReusableResolution(TypeDefinition.java:213)
  3. 	at org.hibernate.boot.model.TypeDefinition.resolve(TypeDefinition.java:113)
  4. 	at org.hibernate.mapping.BasicValue.interpretExplicitlyNamedType(BasicValue.java:382)
  5. 	at org.hibernate.mapping.BasicValue.resolve(BasicValue.java:168)
  6. 	at org.hibernate.mapping.BasicValue.getType(BasicValue.java:155)
  7. 	at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:453)
  8. 	at org.hibernate.mapping.Property.isValid(Property.java:223)
  9. 	at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:624)
  10. 	at org.hibernate.mapping.RootClass.validate(RootClass.java:267)
  11. 	at org.hibernate.boot.internal.MetadataImpl.validate(MetadataImpl.java:353)
  12. 	at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:452)
  13. 	at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:730)
  14. 	at com.go_task.database.HibernateUtil.getSessionFactory(HibernateUtil.java:29)
  15. 	at com.go_task.dao.Test.main(Test.java:15)
  17. Process finished with exit code 0
英文:

I have 2 models. One is the User model and another is the Task model. I'm trying to obtain "one to many" bidirectional relations. But even before doing that when I'm trying to create a user from Test.java class. I'm having an exception.

Named type [com.go_task.entity.User@5b4d25e7] did not implement BasicType nor UserType

How can I fix this?

User.java

  1. package com.go_task.entity;
  4. import javax.persistence.*;
  5. import java.io.Serializable;
  6. import java.util.ArrayList;
  7. import java.util.List;
  10. @Entity
  11. @Table(name = &quot;users&quot;)
  12. public class User implements Serializable {
  14.     @Id
  15.     @GeneratedValue
  16.     private int id;
  18.     @Column(name = &quot;name&quot;)
  19.     private String name;
  21.     @Column(name = &quot;email&quot;)
  22.     private String email;
  24.     @Column(name = &quot;password&quot;)
  25.     private String password;
  27.     @OneToMany(mappedBy = &quot;user&quot;, cascade = CascadeType.ALL)
  28.     private List&lt;Task&gt; tasks = new ArrayList&lt;&gt;();
  30.     public User() {}
  32.     public User(int id, String name, String email, String password) {
  33.         this.id = id;
  34.         this.name = name;
  35.         this.email = email;
  36.         this.password = password;
  37.     }
  39.     public User(String name, String email, String password) {
  40.         this.name = name;
  41.         this.email = email;
  42.         this.password = password;
  43.     }
  45.     @Id
  46.     public int getId() {
  47.         return id;
  48.     }
  50.     public void setId(int id) {
  51.         this.id = id;
  52.     }
  54.     public String getName() {
  55.         return name;
  56.     }
  58.     public void setName(String name) {
  59.         this.name = name;
  60.     }
  62.     public String getEmail() {
  63.         return email;
  64.     }
  66.     public void setEmail(String email) {
  67.         this.email = email;
  68.     }
  70.     public String getPassword() {
  71.         return password;
  72.     }
  74.     public void setPassword(String password) {
  75.         this.password = password;
  76.     }
  78.     public List&lt;Task&gt; getTasks() {
  79.         return tasks;
  80.     }
  82.     public void setTasks(List&lt;Task&gt; tasks) {
  83.         this.tasks = tasks;
  84.     }
  86.     public void addTask(Task task) {
  87.         tasks.add(task);
  88.         task.setUser(this);
  89.     }
  91.     public void removeTask(Task task) {
  92.         tasks.remove(task);
  93.         task.setUser(this);
  94.     }
  95. }

Task.java

  1. package com.go_task.entity;
  4. import javax.persistence.*;
  5. import java.io.Serializable;
  8. @Entity
  9. @Table(name = &quot;tasks&quot;)
  10. public class Task implements Serializable {
  12.     @Id
  13.     @GeneratedValue
  14.     private int id;
  16.     @Column(name = &quot;title&quot;)
  17.     private String title;
  19.     @ManyToOne
  20.     private User user;
  22.     public Task() {}
  24.     public Task(int id, String title) {
  25.         this.id = id;
  26.         this.title = title;
  27.     }
  29.     public Task(String title) {
  30.         this.title = title;
  31.     }
  33.     @Id
  34.     public int getId() {
  35.         return id;
  36.     }
  38.     public void setId(int id) {
  39.         this.id = id;
  40.     }
  42.     public String getTitle() {
  43.         return title;
  44.     }
  46.     public void setTitle(String title) {
  47.         this.title = title;
  48.     }
  50.     public User getUser() {
  51.         return user;
  52.     }
  54.     public void setUser(User user) {
  55.         this.user = user;
  56.     }
  57. }

HibernateUtil.java class

  1. package com.go_task.database;
  3. import com.go_task.entity.Task;
  4. import com.go_task.entity.User;
  5. import org.hibernate.SessionFactory;
  6. import org.hibernate.boot.registry.StandardServiceRegistryBuilder;
  7. import org.hibernate.cfg.Configuration;
  8. import org.hibernate.service.ServiceRegistry;
  10. public class HibernateUtil {
  12.     private static SessionFactory sessionFactory = null;
  14.     public static SessionFactory getSessionFactory() {
  15.         if (sessionFactory == null) {
  16.             try {
  17.                 Configuration configuration = new Configuration();
  18.                 configuration.configure(&quot;db/hibernate.cfg.xml&quot;);
  19.                 configuration.addAnnotatedClass(User.class).addAnnotatedClass(Task.class);
  21.                 ServiceRegistry serviceRegistry = new StandardServiceRegistryBuilder()
  22.                         .applySettings(configuration.getProperties()).build();
  23.                 System.out.println(&quot;Hibernate Java Config serviceRegistry created&quot;);
  24.                 sessionFactory = configuration.buildSessionFactory(serviceRegistry);
  25.                 System.out.println(sessionFactory);
  26.                 return sessionFactory;
  28.             } catch (Exception e) {
  29.                 e.printStackTrace();
  30.             }
  31.         }
  32.         return sessionFactory;
  33.     }
  34. }

Test.java

  1. package com.go_task.dao;
  3. import com.go_task.database.HibernateUtil;
  4. import com.go_task.entity.User;
  5. import org.hibernate.Session;
  6. import org.hibernate.Transaction;
  8. public class Test {
  10.     public static void main(String[] args) {
  11.         User user1 = new User(&quot;Name&quot;, &quot;email&quot;, &quot;pass&quot;);
  13.         Transaction transaction = null;
  15.         try (Session session = HibernateUtil.getSessionFactory().openSession()) {
  16.             transaction = session.beginTransaction();
  17.             session.save(user1);
  18.             transaction.commit();
  19.         } catch (Exception exception) {
  20.             if (transaction != null) transaction.rollback();
  21.             exception.getStackTrace();
  22.         }
  23.     }
  24. }

hibernate.cfg.xml

  1. &lt;?xml version=&quot;1.0&quot; encoding=&quot;utf-8&quot;?&gt;
  2. &lt;!DOCTYPE hibernate-configuration PUBLIC &quot;-//Hibernate/Hibernate Configuration DTD 3.0//EN&quot; &quot;http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd&quot;&gt;
  3. &lt;hibernate-configuration&gt;
  4.     &lt;session-factory&gt;
  5.         &lt;property name=&quot;hibernate.connection.driver_class&quot;&gt;com.mysql.cj.jdbc.Driver&lt;/property&gt;
  6.         &lt;property name=&quot;hibernate.connection.url&quot;&gt;jdbc:mysql://localhost:3306/otm_dm&lt;/property&gt;
  7.         &lt;property name=&quot;hibernate.connection.username&quot;&gt;root&lt;/property&gt;
  8.         &lt;property name=&quot;hibernate.connection.password&quot;&gt;root&lt;/property&gt;
  9.         &lt;property name=&quot;hibernate.dialect&quot;&gt;org.hibernate.dialect.MySQL5Dialect&lt;/property&gt;
  10.         &lt;property name=&quot;show_sql&quot;&gt;false&lt;/property&gt;
  11.     &lt;/session-factory&gt;
  12. &lt;/hibernate-configuration&gt;

When I'm trying to run Test.java class, I'm having the exception below:

  1. java.lang.IllegalArgumentException: Named type [com.go_task.entity.User@5b4d25e7] did not implement BasicType nor UserType
  2. 	at org.hibernate.boot.model.TypeDefinition.createReusableResolution(TypeDefinition.java:213)
  3. 	at org.hibernate.boot.model.TypeDefinition.resolve(TypeDefinition.java:113)
  4. 	at org.hibernate.mapping.BasicValue.interpretExplicitlyNamedType(BasicValue.java:382)
  5. 	at org.hibernate.mapping.BasicValue.resolve(BasicValue.java:168)
  6. 	at org.hibernate.mapping.BasicValue.getType(BasicValue.java:155)
  7. 	at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:453)
  8. 	at org.hibernate.mapping.Property.isValid(Property.java:223)
  9. 	at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:624)
  10. 	at org.hibernate.mapping.RootClass.validate(RootClass.java:267)
  11. 	at org.hibernate.boot.internal.MetadataImpl.validate(MetadataImpl.java:353)
  12. 	at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:452)
  13. 	at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:730)
  14. 	at com.go_task.database.HibernateUtil.getSessionFactory(HibernateUtil.java:29)
  15. 	at com.go_task.dao.Test.main(Test.java:15)
  17. Process finished with exit code 0

答案1

得分: 2

添加带有连接列名称和引用列名称的@JoinColumn。

  1. @Entity
  2. @Table(name = "tasks")
  3. public class Task implements Serializable {
  5.     // ...
  7.     @ManyToOne
  8.     @JoinColumn(name = "user_id", referencedColumnName = "id")
  9.     private User user;
  10.     
  11.     // ...
  12. }
英文:

Add @JoinColumn with join column name and reference column name.

  1. @Entity
  2. @Table(name = &quot;tasks&quot;)
  3. public class Task implements Serializable {
  5.     // ...
  7.     @ManyToOne
  8.     @JoinColumn(name = &quot;user_id&quot;, referencedColumnName = &quot;id&quot;)
  9.     private User user;
  10.     
  11.     // ...
  12. }

答案2

得分: 0

我在getTasks()方法前添加了@OneToMany注解，并在getUser()方法前添加了@ManyToOne注解。之后问题得到解决，现在它正常工作了。但是关于异常还不太清楚。

还有一件事，我使用的是Hibernate版本6 alpha！

英文:

I have added @OneToMany annotation before the getTasks() method and @ManyToOne annotation before getUser() method. After that it solved my problem. It's working now. But not clear about the exception though.

One more thing, I have used Hibernate Version 6 alpha!

huangapple
  • 本文由 发表于 2020年9月25日 22:45:29
  • 转载请务必保留本文链接：https://go.coder-hub.com/64066402.html
  • hibernate
  • hibernate-onetomany
  • java
  • jpa
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