英文:
How to make an HTTP request in Java and ignore the body
问题
更具体地说，我指的是仅在网络上传输HTTP头部并在客户端接收响应正文之前停止通信。
示例
客户端发出请求
GET / HTTP/1.1
Host: example.com
Connection: Keep-Alive
User-Agent: Apache-HttpClient/UNAVAILABLE (Java/1.8.0_262)
Accept-Encoding: gzip,deflate
然后在网络上传输的响应只是
HTTP/1.1 200 OK
Date: Wed, 23 Sep 2020 22:41:21 GMT
Server: Apache
Expires: Sun, 19 Nov 1978 05:00:00 GMT
Cache-Control: public, max-age=10800
Content-Language: en
Vary: Cookie,Accept-Encoding
Content-Encoding: gzip
Content-Type: text/html; charset=utf-8
Age: 1865
grace: none
Content-Length: 9213
Connection: keep-alive
Accept-Ranges: bytes
英文:
To be more specific, I mean specifically to just consume the HTTP headers over the network and stop the communication before the client receives the response body.
Example
Client makes a request
GET / HTTP/1.1
Host: example.com
Connection: Keep-Alive
User-Agent: Apache-HttpClient/UNAVAILABLE (Java/1.8.0_262)
Accept-Encoding: gzip,deflate
Then the response over the network is just
HTTP/1.1 200 OK
Date: Wed, 23 Sep 2020 22:41:21 GMT
Server: Apache
Expires: Sun, 19 Nov 1978 05:00:00 GMT
Cache-Control: public, max-age=10800
Content-Language: en
Vary: Cookie,Accept-Encoding
Content-Encoding: gzip
Content-Type: text/html; charset=utf-8
Age: 1865
grace: none
Content-Length: 9213
Connection: keep-alive
Accept-Ranges: bytes
答案1
得分: 1
Http协议有六种方法，其中一种方法是'HEAD'。您可以尝试使用HEAD方法而不是GET方法。
另一种愚蠢的方法是：声明一个网络接口，然后返回空字符串。就像这样：
// 一个网络接口
String result = "";
return result;
英文:
Http protocol has six method, one of the methods is 'HEAD'. You can try use HEAD method instead of GET method.
And another stupid way : declare a web interface, and return null string.Like this:
// a web interface
String result = "";
return result;
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论