用Java中的for循环将一个数字乘以n个值

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英文:

Multiply a number by n values in a for loop in Java

问题

我有:

salary = 2000;
n = salary / 200 = 10 // 循环次数;
contribution = 0.1, 0.2, 0.3, 0.4...;

我需要创建一个 for 循环,计算工资 x 缴纳比例的总和,如下所示:

工资 x 缴纳比例1 = 500x0.1
工资 x 缴纳比例2 = 500x0.2
...等等...

这是我的类中的一个方法:

public static double pensionContribution(double salary) {

    double n = salary / 200;
    int n_round = (int) Math.floor(n);

    int start = 1;
    List<Integer> n_list = IntStream.rangeClosed(start, n_round)
            .boxed().collect(Collectors.toList());

    double counter = 0.1;

    for (int i = 0; i < n_list.size(); i++) {
        System.out.println(n_list.get((int) (salary * counter)));
    }
    
    counter = counter + 0.1;
    // 需要所有 (salary*counter) 值的总和
    
    return n_round;

}

谢谢!

英文:

I have:

salary = 2000;
n= salary/200 = 10 //number of loops;
contribution = 0.1, 0.2, 0.3, 0.4...;

I need to make a for loop that gets the sum of salary x contribution as:

salary x contribution1 = 500x0.1
salary x contribution2 = 500x0.2
...etc...

this is a method of my class:


public static double pensionContribution(double salary) {
		
		
	double n = salary/200;
	int n_round = (int) Math.floor(n);
		
	int start = 1;
	List&lt;Integer&gt; n_list = IntStream.rangeClosed(start, n_round)
			    .boxed().collect(Collectors.toList());
		
		
	double counter = 0.1;
		
	for (int i = 0; i &lt; n_list.size(); i++) {
           System.out.println(n_list.get((int) (salary*counter)));
                 
    }
		counter = counter + 0.1;
		//need the sum of all values of (salary*counter)
		
	return n_round;
			
	}

Thanks!

答案1

得分: 0

你可以使用这个循环:

    for(int i = 0; i < [循环次数]; i++){
    
         结果乘积 = (工资*计数器)
         总和 = 总和 + 结果乘积
         计数器 = 计数器 + 0.1
    
    }
    返回 总和;

你将得到所有乘法运算的结果总和。不知道为什么你需要一个列表,但这将给你乘法结果的总和。

英文:

you can use this loop:

for(int i = 0;i &lt; [times to loop];i++){

     resultofmultiplication = (salary*counter)
     sum = sum + resultofmultiplication
     counter = counter + 0.1

}
return sum;

you will get all the results from the multiplications summed. idk why you need a list but this will give you the sum of the multiplications

答案2

得分: 0

对于列表中的每个n,您需要计算工资n0.1,并将所有结果求和。
这可以在一个流中完成:

public static double pensionContribution(double salary) {
    double n = salary / 200;
    int n_round = (int) Math.floor(n);
    return IntStream.rangeClosed(1, n_round).mapToDouble(i -> salary * i * 0.1).sum();
}
英文:

For each n in the list you need to calculate salaryn0.1 and sum all.
This can be done in one stream:

public static double pensionContribution(double salary) {
    double n = salary/200;
    int n_round = (int) Math.floor(n);
	return IntStream.rangeClosed(1, n_round).mapToDouble(i-&gt;salary*i*0.1).sum();
}

huangapple
  • 本文由 发表于 2020年9月22日 22:47:55
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