英文:
Basic Authentication for JAVA Application using OkHttp
问题
以下是翻译好的部分：
首先，我想使用 OkHttp 对我的 Java 应用进行身份验证，然后在身份验证之后，响应会返回一个会话 ID（密钥），我想在后续的 API 调用中使用这个会话 ID。以下是我用来实现这一目标的代码。
String url = "我的应用程序 URL";
String username = "xxx";
String password = "zzz";
String userpass = username + ":" + password;
String basicAuth = "Basic " + new String(Base64.getEncoder().encode(userpass.getBytes()));
OkHttpClient client = new OkHttpClient();
Response response;
Request request = new Request.Builder()
.url(url)
.addHeader("Authorization", basicAuth)
.build();
response = client.newCall(request).execute();
if (!response.isSuccessful()) throw new IOException("意外的代码 " + response);
System.out.println(response.body().string());
但是它抛出了一个错误，错误信息如下：
{"responseStatus":"FAILURE","responseMessage":"请求方法 'GET' 不受支持","errorCodes":null,"errors":[{"type":"METHOD_NOT_SUPPORTED","message":"请求方法 'GET' 不受支持"}],"errorType":"GENERAL"}
请问是否有人可以帮助我解决这个问题？或者如果有其他方法可以使用 OkHttp 对 Java 应用进行身份验证，那么请提供建议…
英文:
First I wanted to authenticate my java application using OkHttp and then after authentication the response returns a session ID(key) that I wanted to use in subsequent API calls. below is the code that I am using to achieve this.
String url = "my application url";
String username = "xxx";
String password = "zzz";
String userpass = username + ":" + password;
String basicAuth = "Basic :" + new String(Base64.getEncoder().encode(userpass.getBytes()));
OkHttpClient client = new OkHttpClient();
Response response ;
Request request = new Request.Builder()
.url(url)
.addHeader("Authorization", basicAuth)
.build();
response = client.newCall(request).execute();
if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);
System.out.println(response.body().string());
but its throwing an error saying
{"responseStatus":"FAILURE","responseMessage":"Request method 'GET' not supported","errorCodes":null,"errors":[{"type":"METHOD_NOT_SUPPORTED","message":"Request method 'GET' not supported"}],"errorType":"GENERAL"}
can someone please help me to solve this. or if any have any other idea to authenticate a java application using okhttp then please suggest...
答案1
得分: 3
你应该使用辅助类来避免大部分用户名和密码逻辑。
链接：https://github.com/square/okhttp/blob/master/samples/guide/src/main/java/okhttp3/recipes/Authenticate.java
String credential = Credentials.basic("jesse", "password1");
return response.request().newBuilder()
.header("Authorization", credential)
.build();
假设这个API是POST而不是GET，也遵循以下步骤：
链接：https://github.com/square/okhttp/blob/master/samples/guide/src/main/java/okhttp3/recipes/PostString.java
Request request = new Request.Builder()
.url("https://api.github.com/markdown/raw")
.post(RequestBody.create(postBody, MEDIA_TYPE_MARKDOWN))
.build();
英文:
You should use the helper classes to avoid most of the logic for username and password.
String credential = Credentials.basic("jesse", "password1");
return response.request().newBuilder()
.header("Authorization", credential)
.build();
Assuming this API is POST and not GET also follow
Request request = new Request.Builder()
.url("https://api.github.com/markdown/raw")
.post(RequestBody.create(postBody, MEDIA_TYPE_MARKDOWN))
.build();
答案2
得分: 0
你已经完全正确了。只需要进行一个小的修正：
String basicAuth = "Basic " + new String(Base64.getEncoder().encode(userpass.getBytes()));
也就是说，你只需要在 .addHeader("Authorization", basicAuth) 部分中删除多余的 ':'，因为这已经在其中得到了处理。
英文:
You had it all right already. Just a small fix needed:
String basicAuth = "Basic " + new String(Base64.getEncoder().encode(userpass.getBytes()));
i.e you just need to remove extra ':' as it's already taken care of in .addHeader("Authorization", basicAuth) part.
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论