英文:
How to display the numbers of integers that the user input?
问题
以下是翻译好的内容：
示例输出如下：
[![在此输入图片描述][1]][1]
int nValue, x;
Scanner input = new Scanner(System.in);
System.out.print("输入 n 的值：");
nValue = input.nextInt();
for (x = 1; x == nValue; x++){
System.out.println("输入数字 " + x + ": ");
}
非常感谢任何帮助。
请注意，为了使代码更加清晰，我稍微修改了代码中的一些表达方式。
英文:
Sample output is this 
int nValue, x;
Scanner input = new Scanner(System.in);
System.out.print("Enter value of n: ");
nValue = input.nextInt();
for (x = 1; x == nValue; x++){
System.out.println("Enter number" + x + ": ");
Any help is much appreciated.
答案1
得分: 1
不确定这是否完全回答了您所要问的问题，但它应该会给出示例输出：
// 这里也不需要 x 变量
int nValue;
Scanner input = new Scanner(System.in);
System.out.print("输入 n 的值：");
nValue = input.nextInt();
// 我们递增 x，直到达到 nValue
for (int x = 1; x <= nValue; x++){
System.out.println("输入数字 " + x + "：");
}
英文:
Not sure if this answers exactly what you are trying to ask, but it should give the sample output:
// also we dont need the x variable up here
int nValue;
Scanner input = new Scanner(System.in);
System.out.print("Enter value of n: ");
nValue = input.nextInt();
//we increment x, until we reach the `nValue`
for (int x = 1; x <= nValue; x++){
System.out.println("Enter number" + x + ": ");
答案2
得分: 0
Scanner input = new Scanner(System.in);
System.out.print("输入 n 的值：");
int n = input.nextInt();
System.out.print("输入 " + n + " 个整数：\n");
System.out.print("输入数字 1：");
int num1 = input.nextInt();
System.out.print("输入数字 2：");
int num2 = input.nextInt();
System.out.print("输入数字 3：");
int num3 = input.nextInt();
System.out.print("输入数字 4：");
int num4 = input.nextInt();
System.out.print("输入数字 5：");
int num5 = input.nextInt();
英文:
Scanner input = new Scanner(System.in);
System.out.print("Enter value of n: ");
int n =input.nextInt();
System.out.print("Enter " + n + " integers: \n");
System.out.print("Enter number 1:");
int num1 = input.nextInt();
System.out.print("Enter number 2:");
int num2 = input.nextInt();
System.out.print("Enter number 3:");
int num3 = input.nextInt();
System.out.print("Enter number 4:");
int num4 = input.nextInt();
System.out.print("Enter number 5:");
int num5 = input.nextInt();
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