应用在运行onActivityResult后进入后台。

huangapple
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英文:

App goes to the background after running onActivityResult

问题

  1. @Override
  2. public void onActivityResult(int requestCode, int resultCode, Intent data) {
  3.     super.onActivityResult(requestCode, resultCode, data);
  4.     switch (requestCode) {
  5.         case RC_SIGN_IN:
  6.             if (resultCode == RESULT_CANCELED) {
  7.                 finish();
  8.             } else {
  9.                 System.out.println("Here" + Integer.toString(requestCode) + Integer.toString(resultCode));
  10.             }
  11.         case RC_START_APP:
  12.             if (resultCode == RESULT_LOGOUT) {
  13.                 signout();
  14.             } else {
  15.                 finish();
  16.             }
  17.     }
  18. }
英文:

I am using FirebaseUI to log in to my app. On returning from the login activity, the following onActivityResult-override prints Here1-1, which is as expected. However, immediately after, the activity finishes, which is not what I want. I feel really lost, does anyone have any idea what could be happening?

  1. @Override
  2. public void onActivityResult(int requestCode, int resultCode, Intent data){
  3.     super.onActivityResult(requestCode,resultCode,data);
  4.     switch (requestCode) {
  5.         case RC_SIGN_IN:
  6.             if (resultCode == RESULT_CANCELED) {
  7.                 finish();
  8.             } else {
  9.                 System.out.println("Here" + Integer.toString(requestCode) + Integer.toString(resultCode));
  10.             }
  11.         case RC_START_APP:
  12.             if (resultCode == RESULT_LOGOUT) {
  13.                 signout();
  14.             } else {
  15.                 finish();
  16.             }
  17.     }
  18. }

答案1

得分: 2

你的案例需要添加break语句来停止执行，以防止它们继续执行到下一个案例。你的活动实际上是因为在第二个RC_START_APP案例中执行了finish()而结束的。

  1.     switch (requestCode) {
  2.         case RC_SIGN_IN:
  3.             if (resultCode == RESULT_CANCELED) {
  4.                 finish();
  5.             } else {
  6.                 System.out.println("Here" + Integer.toString(requestCode) + Integer.toString(resultCode));
  7.             }
  8.             break;  // 在这里添加break
  9.         case RC_START_APP:
  10.             if (resultCode == RESULT_LOGOUT) {
  11.                 signout();
  12.             } else {
  13.                 finish();
  14.             }
  15.             break;  // 在这里添加break
  16.     }
英文:

Your cases need a break to stop execution so they don't fall through to the next case. Your activity is actually just finishing due to executing the finish() in the second RC_START_APP case.

  1.     switch (requestCode) {
  2.         case RC_SIGN_IN:
  3.             if (resultCode == RESULT_CANCELED) {
  4.                 finish();
  5.             } else {
  6.                 System.out.println("Here" + Integer.toString(requestCode) + Integer.toString(resultCode));
  7.             }
  8.             break;  // add this break
  9.         case RC_START_APP:
  10.             if (resultCode == RESULT_LOGOUT) {
  11.                 signout();
  12.             } else {
  13.                 finish();
  14.             }
  15.             break;  // add this break
  16.     }

huangapple
  • 本文由 发表于 2020年9月20日 01:33:03
  • 转载请务必保留本文链接：https://go.coder-hub.com/63971582.html
  • android
  • firebase
  • firebase-authentication
  • firebaseui
  • java
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