使用Java 8 Streams进行哈希映射对象列表迭代

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英文:

Hash Map object list iteration using Java 8 Streams

问题

我必须迭代HashMap对象列表。如果映射对象的值为true,则必须使用Java 8 Stream API将该条目返回到一个映射哈希对象中。

public class HashMapCheck {
    static Map<String, Boolean> map;
    static Map<String, Boolean> map2;
    static List<Map> objMap;

    public static void main(String args[]) {
        map = new HashMap<String, Boolean>();
        map.put("1", true);
        map.put("2", false);

        map2 = new HashMap<String, Boolean>();
        map2.put("4", true);
        map2.put("5", true);
        objMap = new ArrayList<Map>();
        objMap.add(map);
        objMap.add(map2);

        // 迭代部分
    }
}
英文:

I have to iterate the HashMap object list. if the map object value is true then I have to return that entry to one map Hash object using java 8 stream API


public class HashMapCheck {
	static Map&lt;String, Boolean&gt; map;
	static Map&lt;String, Boolean&gt; map2;
	static List&lt;Map&gt; objMap;

	public static void main(String args[]) {
		map = new HashMap&lt;String, Boolean&gt;();
		map.put(&quot;1&quot;, true);
		map.put(&quot;2&quot;, false);

		map2 = new HashMap&lt;String, Boolean&gt;();
		map2.put(&quot;4&quot;, true);
		map2.put(&quot;5&quot;, true);
		objMap = new ArrayList&lt;Map&gt;();
		objMap.add(map);
		objMap.add(map2);

		//Iterate
	}
}

答案1

得分: 0

我对Java流处理不是很熟悉,所以也许这不是最简洁的解决方案,但以下是我使用流处理想出来的代码,以获取我认为你想要的结果:

public class HashMapCheck {
    static Map<String, Boolean> map;
    static Map<String, Boolean> map2;
    static List<Map<String, Boolean>> objMap;

    public static void main(String[] args) {

        map = new HashMap<>();
        map.put("1", true);
        map.put("2", false);

        map2 = new HashMap<>();
        map2.put("4", true);
        map2.put("5", true);
        objMap = new ArrayList<>();
        objMap.add(map);
        objMap.add(map2);

        Map<String, Boolean> result = objMap.stream().flatMap(x -> x.entrySet().stream()).filter(Map.Entry::getValue).
                collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue));

        System.out.println(result);

    }
}

结果:

{1=true, 4=true, 5=true}
英文:

I'm not an expert with Java streams, so maybe this is not the minimal solution, but here's what I came up with using streams to get what I think you want:

public class HashMapCheck {
    static Map&lt;String, Boolean&gt; map;
    static Map&lt;String, Boolean&gt; map2;
    static List&lt;Map&lt;String, Boolean&gt;&gt; objMap;

    public static void main(String[] args) {

        map = new HashMap&lt;&gt;();
        map.put(&quot;1&quot;, true);
        map.put(&quot;2&quot;, false);

        map2 = new HashMap&lt;&gt;();
        map2.put(&quot;4&quot;, true);
        map2.put(&quot;5&quot;, true);
        objMap = new ArrayList&lt;&gt;();
        objMap.add(map);
        objMap.add(map2);

        Map&lt;String, Boolean&gt; result = objMap.stream().flatMap(x -&gt; x.entrySet().stream()).filter(Map.Entry::getValue).
                collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue));

        System.out.println(result);

    }
}

Result:

{1=true, 4=true, 5=true}

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  • 本文由 发表于 2020年9月20日 01:32:16
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