Java(服务器)Socket多房间

huangapple go评论70阅读模式
英文:

Java (Server)Socket multi room

问题

我正在尝试寻找一种创建多房间 Socket 的方法。这样用户就可以在不同的房间中与其他用户聊天,或者与其他用户私下聊天。是否有办法使用 java.net.Socket 和/或 java.net.ServerSocket 来实现这一点?

最佳方法是什么?我是否需要为每个房间和私人聊天都开启一个新端口?

我可以通过我的集成开发环境看到有一个 Socket getChannel() 方法,但是找不到有关此方法的任何信息。
也许我使用了错误的关键词。

我希望有人能帮助我解决这个问题 Java(服务器)Socket多房间

英文:

I am trying to find a way to create a multiroom Socket. So users can chat in different rooms or privately with other users. Is there a way to do this with the java.net.Socket and/or java.net.ServerSocket?

What is the best way to do this? Do I need to open a new port for each room and private chat?

I can see through my IDE that there is a Socket getChannel(), but unable to find anything about this.
Perhaps I am looking with the wrong words.

I hope someone can help me with this Java(服务器)Socket多房间

答案1

得分: 1

是的,有一种方法可以做到这一点。你需要为每个连接到服务器的用户创建一个新的线程,并将用户名和套接字存储在一个映射<username,socket>中,然后如果有人想要向特定用户发送消息,只需从映射中获取套接字并向该用户发送消息。

实现为所有用户创建线程的最简单方法如下:

ServerSocket serverSocket = new ServerSocket(6666);
while (true){
    new User(serverSocket.accept()).start();
}

然后你只需要重写run()方法,监视用户是否向服务器发送任何消息,并将其传递给消息中指定的用户。

英文:

Yea, there's a way to do it. You need to create a new Thread for every user that connect to your server and store the username and socket in a map<username,socket> then if someone wan't to send a message to specific user, you just pick up socket from a map and send a message to this user.

Simplest way to achieve a thread for all users looks like

ServerSocket serverSocket = new ServerSocket(6666);
while (true){
    new User(serverSocket.accept()).start();
}

Then you just need to ovveride run() method to monitor if user send any message to our server and pass it to a user witch is specified in message.

huangapple
  • 本文由 发表于 2020年9月18日 22:13:44
  • 转载请务必保留本文链接:https://go.coder-hub.com/63957434.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定