英文:
Converting the code into a function and link problem
问题
这段代码展示了一个图表。您想将这段代码分割成一个函数，以便在调用该函数时执行代码并显示图形。不过在代码中有一些关于主要部分、舞台（stage）、场景（scene）等方面的链接，可能不太容易进行分割。如果您尝试过但仍然遇到问题，可以提供更多具体的信息，以便我能够更好地帮助您。感谢您的理解。
英文:
I have a problem maybe it is simple .. I hope for your help
This code below shows a graph.
public class LineChartSample extends Application {
@Override public void start(Stage stage) {
stage.setTitle("Line Chart Sample");
final CategoryAxis xAxis = new CategoryAxis();
final NumberAxis yAxis = new NumberAxis();
xAxis.setLabel("Month");
final LineChart<String,Number> lineChart =
new LineChart<String,Number>(xAxis,yAxis);
lineChart.setTitle("Stock Monitoring, 2010");
XYChart.Series series1 = new XYChart.Series();
series1.setName("Portfolio 1");
series1.getData().add(new XYChart.Data("Jan", 23));
series1.getData().add(new XYChart.Data("Feb", 14));
series1.getData().add(new XYChart.Data("Mar", 15));
series1.getData().add(new XYChart.Data("Apr", 24));
series1.getData().add(new XYChart.Data("May", 34));
series1.getData().add(new XYChart.Data("Jun", 36));
series1.getData().add(new XYChart.Data("Jul", 22));
series1.getData().add(new XYChart.Data("Aug", 45));
series1.getData().add(new XYChart.Data("Sep", 43));
series1.getData().add(new XYChart.Data("Oct", 17));
series1.getData().add(new XYChart.Data("Nov", 29));
series1.getData().add(new XYChart.Data("Dec", 25));
XYChart.Series series2 = new XYChart.Series();
series2.setName("Portfolio 2");
series2.getData().add(new XYChart.Data("Jan", 33));
series2.getData().add(new XYChart.Data("Feb", 34));
series2.getData().add(new XYChart.Data("Mar", 25));
series2.getData().add(new XYChart.Data("Apr", 44));
series2.getData().add(new XYChart.Data("May", 39));
series2.getData().add(new XYChart.Data("Jun", 16));
series2.getData().add(new XYChart.Data("Jul", 55));
series2.getData().add(new XYChart.Data("Aug", 54));
series2.getData().add(new XYChart.Data("Sep", 48));
series2.getData().add(new XYChart.Data("Oct", 27));
series2.getData().add(new XYChart.Data("Nov", 37));
series2.getData().add(new XYChart.Data("Dec", 29));
XYChart.Series series3 = new XYChart.Series();
series3.setName("Portfolio 3");
series3.getData().add(new XYChart.Data("Jan", 44));
series3.getData().add(new XYChart.Data("Feb", 35));
series3.getData().add(new XYChart.Data("Mar", 36));
series3.getData().add(new XYChart.Data("Apr", 33));
series3.getData().add(new XYChart.Data("May", 31));
series3.getData().add(new XYChart.Data("Jun", 26));
series3.getData().add(new XYChart.Data("Jul", 22));
series3.getData().add(new XYChart.Data("Aug", 25));
series3.getData().add(new XYChart.Data("Sep", 43));
series3.getData().add(new XYChart.Data("Oct", 44));
series3.getData().add(new XYChart.Data("Nov", 45));
series3.getData().add(new XYChart.Data("Dec", 44));
Scene scene = new Scene(lineChart,800,600);
lineChart.getData().addAll(series1, series2, series3);
stage.setScene(scene);
stage.show();
}
public static void main(String[] args) {
launch(args);
}
}
But I want to divide this code into a function .. when I call it, it executes the code and the graphic appears
I tried many times, but there are links in the code and I do not know how to collect them, especially in the main part and the stage and scene part
I hope for help
Thanks
答案1
得分: 1
依我看，您可以从您的代码中提取三个函数。
首先是 XYChart.Series getSeries(seriesName)，它返回一个填充了数据的 Series 对象。
其次是 getScene(lineCharts, width, height)，它返回一个添加了系列的 Scene 对象。
第三是 showScene(stage)，在这个方法中，您可以使用上述方法设置您的舞台（stage），然后调用 stage.show() 来显示舞台。
英文:
In my opinion, you can extract three function from you code.
First is XYChart.Series getSeries(seriesName) which return a Series object with filled data.
Second is getScene(lineCharts,width,height) which return a Scene object with added series.
Third is showScene(stage), in this method you setup your stage with the above method and call stage.show() to show the stage.
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