从Java的用户列表中移除用户。

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英文:

Remove User from list of users in java

问题

我对Java还不熟悉,所以请原谅我的解释可能不够清楚,但我有一个列表:

private LinkedList<User> users = new LinkedList<User>();

还有一个名为removeUser的方法:

private void removeUser() {
    System.out.println("All Users: ");
    viewUsers();
    System.out.print("Please enter the ID of the user to be removed: ");
    int choice = In.nextInt();
    for (User user : users) {
        if (users.contains(choice)) {
            users.remove(choice);
        }
    }
}

现在当我运行代码时,它成功地打印出了所有内容。但是当我检查列表内容时,什么也没有改变,我不确定我在代码的移除部分做错了什么。

英文:

I'm new to java, so please excuse me if my explanation is poor but I have a list :

private LinkedList&lt;User&gt; users= new LinkedList&lt;User&gt;();

and a method removeUser:

private void removeUser() {
        System.out.println(&quot;All Users: &quot;);
        viewUsers();
        System.out.print(&quot;Please enter the ID of the user to be removed: &quot;);
        int choice = In.nextInt();
        for (User user : users){ 
            if (users.contains(choice)) { 
                users.remove(choice); 
            } 

        }
    }

Now when I run the code it successfully prints out everything. Yet when I check the list contents, nothing has changed and I'm unsure of what I have done wrong with the removal part of the code.

答案1

得分: 1

另一种解决方案如果你想使用 lambda 表达式和流来移除具有对应 ID 的第一个用户

private void removeUser() {
    System.out.println("所有用户:");
    viewUsers();
    System.out.print("请输入要移除的用户的 ID:");
    int choice = In.nextInt();
    
    users.stream()
         .filter(user -> user.getId() == choice)
         .findFirst()
         .ifPresent(users::remove);
}
英文:

Alternative solution: if you want to use lambda and streams to remove first User with corresponding ID.


private void removeUser() {
    System.out.println(&quot;All Users: &quot;);
    viewUsers();
    System.out.print(&quot;Please enter the ID of the user to be removed: &quot;);
    int choice = In.nextInt();
    
    users.stream()
	 	 .filter(user-&gt;user.getId() == choice)
	     .findFirst()
	     .ifPresent(users::remove);
}

答案2

得分: -1

如果您想从列表中移除某个项目,您不能使用 for-each 循环。参考:https://stackoverflow.com/questions/33582050/what-is-a-difference-between-traditional-loop-and-for-each-loop

我认为您需要相同的操作:

 private void removeUser() {
    System.out.println("所有用户:");
    viewUsers();
    System.out.print("请输入要移除的用户的 ID:");
    int choice = In.nextInt();
    for (int i = 0; i < users.size(); i++){ 
        User user = users.get(i);
        if (user.contains(choice)) { 
            users.remove(i); // 在索引 i 处移除
        } 

    }
}

希望能帮到您!

英文:

If you want remove some item from list you can't use for-each loop. Refer: https://stackoverflow.com/questions/33582050/what-is-a-difference-between-traditional-loop-and-for-each-loop

I think you need same:

 private void removeUser() {
    System.out.println(&quot;All Users: &quot;);
    viewUsers();
    System.out.print(&quot;Please enter the ID of the user to be removed: &quot;);
    int choice = In.nextInt();
    for (int i = 0; i &lt; users.size(); i++){ 
        User user = users.get(i);
        if (user.contains(choice)) { 
            users.remove(i); // remove at index i
        } 

    }
}

Hope can help you!

huangapple
  • 本文由 发表于 2020年9月17日 10:25:03
  • 转载请务必保留本文链接:https://go.coder-hub.com/63930388.html
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