Read in a sentence and print out only words that have the same letter repeated 3 or more times in a row

I wanted to make a program in which only repeats words that has 3 of the same letters back to back. eg the mooonkey raaan through the mounnntains. the program should only repeat mooonkey, raaan

public class Triplets2 {

public static void main(String[] args) {

	Scanner input = new Scanner(System.in);
	System.out.println("write a sentence");
	String in = input.nextLine();
	
	String [] sentence = in.split(" ");
	
	for (int i = 0; i < sentence.length; i++) {
		
		char [] word = sentence[i].toCharArray();
		int counter =0;
		
		for (int s = 0; s < word.length; s++) {
			
			char letter = word
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;
			
			for (int x = 0; x<word.length; x++) {
				
				if (letter == word[x]) {
					counter++;
				}
					else {
						counter = 0;
				}
			}
		}
		if (counter >=3) {
			System.out.print(sentence[i] + ",  ");
		}
	}
}

the program instead just repeats nothing.

Your code is almost correct, the only logical error you made is inside your inner loop you keep resetting your counter variable as soon as you find a letter that is different:

if (letter == word[x]) {
    counter++;
} else {
    counter = 0;
}

So when you iterate over a word like "raaan" your counter will reset when it reaches the very end of the String, because "n" only exists once.
What this means is that you will only be able to detect words that have 3 consecutive letters at the very end (like "Hooo").

The solution is simple:
Once you found 3 consecutive letters in a word you can just stop iterating and checking the rest of your word. At that point you already know that it fits your criteria:

if (letter == word[x]) {
    counter++;
    if(counter >= 3) break; // stop inner loop checking once we found 3 letters
} else {
    counter = 0;
}

Well, if you're just looking for a shorter version of doing this then try this.

• first, split the sentence on one or more white space characters (you should be doing that regardless).
• stream the array and filter on a single character, followed by the same two characters via a back reference to the capture group (see regular expressions for that).
• And print them.

String str =
		"Thiiis is aaaa tesssst of finding worrrrds with more than threeeeee letteeeeers";

Arrays.stream(str.split("\\s+"))
		.filter(s -> s.matches(".*(.)\\.*"))
		.forEach(System.out::println);

Prints

Thiiis
aaaa
tesssst
worrrrds
threeeeee
letteeeeers
		

</details>



# 答案3
**得分**: 0

允许我提出一个与你的略有不同且不使用计数器的解决方案。
```java
Scanner input = new Scanner(System.in);
System.out.println("输入一句话：");
String in = input.nextLine();
String[] sentence = in.split(" ");
for (int i = 0; i < sentence.length; i++) {
    char[] word = sentence[i].toCharArray();
    for (int s = 0; s < word.length - 2; s++) {
        if (word
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 == word
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 && word
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 == word
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) {
            System.out.print(sentence[i] + ", ");
            break;
        }
    }
}

检查当前单词中的当前字母是否与下一个字母和下下个字母相同。如果条件成立，则打印当前单词并继续处理句子中的下一个单词。

Scanner input = new Scanner(System.in);
System.out.println("write a sentence");
String in = input.nextLine();
String[] sentence = in.split(" ");
for (int i = 0; i < sentence.length; i++) {
    char[] word = sentence[i].toCharArray();
    for (int s = 0; s < word.length - 2; s++) {
        if (word[s] == word[s + 1] && word[s] == word[s + 2]) {
            System.out.print(sentence[i] + ",  ");
            break;
        }
    }
}

答案4

得分: 0

因为你要寻找连续的字母，所以你需要从字符 i 开始，然后比较字符 i 处的字符与 i+1 处的字符，以及 i+2 处的字符。如果它们都相等，那么就有一个匹配，并且可以继续。

你可以简化整个函数，如下所示：

public static void main(String[] args) {
  Scanner input = new Scanner(System.in);
  System.out.println("写一个句子");
  String in = input.nextLine();

  List<String> tripleLetter = new ArrayList<>();
  for (String s : in.split(" ")) {
    char[] word = s.toCharArray();
    for (int i = 0; i < word.length - 2; i++) {
      if ((word[i] == word[i+1]) && (word[i] == word[i+2])) {
        tripleLetter.add(s);
        break;
      }
    }
  }

  System.out.println(tripleLetter.stream().collect(Collectors.joining(", ")));
}

public static void main(String[] args) {
  Scanner input = new Scanner(System.in);
  System.out.println("write a sentence");
  String in = input.nextLine();

  List<String> tripleLetter = new ArrayList<>();
  for (String s : in.split(" ")) {
    char[] word = s.toCharArray();
    for (int i = 0; i < word.length - 2; i++) {
      if ((word[i] == word[i+1]) && (word[i] == word[i+2])) {
        tripleLetter.add(s);
        break;
      }
    }
  }

  System.out.println(tripleLetter.stream().collect(Collectors.joining(", ")));
}