Regex max a string till " and not stop at \"

I have a String to be checked for regex :

"field":"Testing, for something \"and something\""

which I want to pattern match and replace with :

"field":"SAFE"

For this, I am trying to pattern match and capture till the last inverted commas. I have tried the following regex, but its not matching :

Pattern p = Pattern.compile("\"field\":\".*?(?!\\\")\"");

New to regex, can anyone suggest what I might be doing wrong? Thanks!

EDIT :
I guess the question was not clear. Apologies. The above is not the end of the string. It can contain more fields in succession :

"field":"Testing, for something \"and something\"", "new_field":"blahblah", ...

output should be :

"field":"SAFE", "new_field":"blahblah", ...

You can do it as follows:

public class Testing {
	public static void main(String[] args) {
		String str = "\"field\":\"Testing, for something \\\"and something\\\"\"";
		str = str.replaceAll("(\"field\":).*", "$1\"SAFE\"");
		System.out.println(str);
	}
}

Output:

"field":"SAFE"

Explanation:

1. (\"field\":) is the first capturing group
2. .* specifies all characters
3. $1 specifies the first capturing group

Update:

Writing this update based on the clarification from OP.

You can use positive lookahead for comma as shown below:

public class Testing {
	public static void main(String[] args) {
		String str = "\"field\":\"Testing, for something \\\"and something\\\"\", \"new_field\":\"blahblah\"";
		str = str.replaceAll("(\"field\":).*(?=,)", "$1\"SAFE\"");
		System.out.println(str);
	}
}

Output:

"field":"SAFE", "new_field":"blahblah"

Here is an example.

$str = '"field":"Testing, for something \"and something\""';
echo preg_replace('/(\"field\":\")(.*)(\")/i', "$1SAFE$3", $str);

Regex is tested: here.