英文:
Android ListView onItemClick show Popup on exact position
问题
我有一个PopupWindow，当我点击ListView上的一个Item时，它会显示为一个下拉菜单：
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
View v = getLayoutInflater().inflate(R.layout.popup_click_menu, null);
final PopupWindow mypopupWindow = new PopupWindow(v, 300, RelativeLayout.LayoutParams.WRAP_CONTENT, true);
mypopupWindow.showAsDropDown(view, -153, 0);
}
结果如下：
我的问题是：我想让弹出窗口的位置是动态的。因此，如果我点击Item的中间部分，它应该显示在中间。我该如何做到这一点？
英文:
I have a PopupWindow which is shown as a drop down when I click a Item on my ListView:
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
View v = getLayoutInflater().inflate(R.layout.popup_click_menu, null);
final PopupWindow mypopupWindow = new PopupWindow(v,300, RelativeLayout.LayoutParams.WRAP_CONTENT, true);
mypopupWindow.showAsDropDown(view, -153, 0);
}
The result is this:
My question is: I want to have a dynamic position of my pop up. So if I click on the middle of the Item then it should be shown in the middle. How can I do that?
答案1
得分: 0
你可以通过使用 TouchListener 来解决这个问题：
list.setOnTouchListener(new OnTouchListener() {
public boolean onTouch(View view, MotionEvent event) {
positionX = (int) event.getX();
return false; // 未消耗，传递给 onClick
}
});
然后你可以在 onItemClick 中使用得到的准确的 x 位置来移动 PopupWindow：
mypopupWindow.showAsDropDown(view, positionX, 0);
英文:
You can solve this with a TouchListener:
list.setOnTouchListener(new OnTouchListener() {
public boolean onTouch(View view, MotionEvent event) {
positionX = (int) event.getX();
return false; // not consumed; forward to onClick
}
});
Then you have the exact x-position and you can move the PopupWindow by onItemClick:
mypopupWindow.showAsDropDown(view, positionX, 0);
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