Getting error The method sort(List<T>) in the type Collections is not applicable for the arguments (List<LinkedInUser>)

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英文:

Getting error The method sort(List<T>) in the type Collections is not applicable for the arguments (List<LinkedInUser>)

问题

@Test
public void sortingTest() throws LinkedInException {
    LinkedInUser Han = new LinkedInUser("Han", "hanpass");
    LinkedInUser LUKE = new LinkedInUser("LUKE", "LUKEpass");
    LinkedInUser leia = new LinkedInUser("leia", "leiapass");
    
    Han.addConnection(LUKE);
    Han.addConnection(leia);
    
    List<LinkedInUser> hansConnections = Han.getConnections();
    
    Collections.sort(hansConnections);
    
    hansConnections.get(0).equals(leia);
    hansConnections.get(1).equals(LUKE);
}
英文:

@Test

public void sortingTest() throws LinkedInException {

LinkedInUser Han = new LinkedInUser(&quot;Han&quot;, &quot;hanpass&quot;);

LinkedInUser LUKE = new LinkedInUser(&quot;LUKE&quot;, &quot;LUKEpass&quot;);

LinkedInUser leia = new LinkedInUser(&quot;leia&quot;, &quot;leiapass&quot;);

Han.addConnection(LUKE);

Han.addConnection(leia);

List&lt;LinkedInUser&gt; hansConnections = Han.getConnections();


Collections.sort(hansConnections);

hansConnections.get(0).equals(leia);

hansConnections.get(1).equals(LUKE);

}

I am getting an error code with my sort, if anyone could provide insight as to how to fix this issue I would appreciate it.

答案1

得分: 4

这个方法的声明如下:

public static <T extends Comparable<? super T>> void sort(List<T> list)

当你使用List<LinkedInUser>调用时,意味着TLinkedInUser,这意味着**LinkedInUser 必须 实现Comparable<LinkedInUser>**(或者是LinkedInUser的某个父类型)。

如果你无法做到这一点,可以调用重载版本,以便提供一个Comparator

public static <T> void sort(List<T> list, Comparator<? super T> c)

如果现在既没有类实现Comparable,也没有提供Comparator,你期望对象按什么顺序排序呢?

英文:

The method is declared as:

public static &lt;T extends Comparable&lt;? super T&gt;&gt; void sort(List&lt;T&gt; list)

When you call with a List&lt;LinkedInUser&gt;, it means that T is a LinkedInUser, which means that LinkedInUser must implement Comparable&lt;LinkedInUser&gt; (or some super-type of LinkedInUser).

If you can't do that, call the overload, so you can supply a Comparator instead:

public static &lt;T&gt; void sort(List&lt;T&gt; list, Comparator&lt;? super T&gt; c)

Right now, without the class implementing Comparable, and without supplying a Comparator, what order did you expect the objects to be sorted in?

答案2

得分: 2

你需要阅读这份Java集合的文档。找到sort方法并查看其工作原理。

你可以做两件事情:

  1. 在你的LinkedinUser类中实现Comparable接口并重写compareTo方法,根据你想要对对象进行排序的方式提供其实现。

  2. 使用Comparator接口,并实现compare方法(使用匿名接口实现)。

英文:

You need to read this documentation of Java Collections. Find the sort method and check how it works.

You can do two things:

  1. Implement Comparable interface in your LinkedinUser class and override compareTo method, providing its implementation according to which you want to sort objects.

  2. Use Comparator interface, and implementing the compare method(using Anonymous Interface Implementations)

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  • 本文由 发表于 2020年9月14日 04:03:59
  • 转载请务必保留本文链接:https://go.coder-hub.com/63875055.html
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