Java ServerSocket OutputStream not flushing

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英文:

Java ServerSocket OutputStream not flushing

问题

Server:

ServerSocket server = new ServerSocket(7788);
Socket client = server.accept();

OutputStream os = client.getOutputStream();

os.write("Hello World".getBytes());
os.flush();
// os.close();

Client:

Socket client = new Socket("localhost", 7788);

byte[] bytes = client.getInputStream().readAllBytes();
String message = new String(bytes);

System.out.println(message);

如果我关闭OutputStream,一切都正常工作,但是我需要在我的项目中多次发送数据。这个问题有解决方法吗?

英文:

My ServerSocket (java.net.ServerSocket) only flushes the data if I close the OutputStream, but if I close the OutputStream, it closes the connection. Here is my code

Server:

ServerSocket server = new ServerSocket(7788);
Socket client = server.accept();

OutputStream os = client.getOutputStream();

os.write("Hello World".getBytes());
os.flush();
// os.close();

Client:

Socket client = new Socket("localhost", 7788);

byte[] bytes = client.getInputStream().readAllBytes();
String message = new String(bytes);

System.out.println(message);

If I close the OutputStream everything works fine, but I need to send data multiple times for my project. Is there a solution for this?

答案1

得分: 1

问题不在于OutputStream(服务器)上的flush(),而在于InputStream(客户端)上的readAllBytes()。根据文档(我加了重点):

> public byte[] readAllBytes() throws IOException
>
> 从输入流中读取所有剩余的字节。此方法会阻塞,直到读取所有剩余字节并检测到流结束,或者抛出异常

只有在close()时才会"发送"“流结束”,这就是为什么只有在close()之后才能读取(打印)消息。

交换单行文本数据的一个非常简单的解决方案是通过'\n'(换行)字符分隔消息,在客户端部分按行从套接字读取,例如:

Server.java

import java.io.OutputStream;
import java.net.ServerSocket;
import java.net.Socket;

public class Server
{
    public static void main(String[] args) throws Exception
    {
        ServerSocket server = new ServerSocket(7788);
        Socket client = server.accept();

        OutputStream os = client.getOutputStream();
        for (int i = 0; i < 5; i++) {
            os.write(String.format("message %d\n", i).getBytes());
            os.flush();

            Thread.sleep(2000);
        }

        os.close();
    }
}

Client.java

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.Socket;

public class Client
{
    public static void main(String[] args) throws Exception
    {
        Socket client = new Socket("localhost", 7788);

        BufferedReader reader = new BufferedReader(new InputStreamReader(client.getInputStream()));
        String message = null;
        while ((message = reader.readLine()) != null)
            System.out.println(message);

        reader.close();
    }
}

$ javac Server.java Client.java
$ java Server

$ java Client
message 0
message 1
message 2
message 3
message 4
$

如果运行上述代码,您将看到消息会以2秒的间隔一个接一个地打印(接收),而readLine()会在读取到\n(换行)字符后立即返回。

如果这对您的用例不可行,我认为您将需要一个更结构化的协议。

英文:

the problem is not the flush() on the OutputStream (server), but rather the readAllBytes() on the InputStream (client). from the docs (emphasis mine):

> public byte[] readAllBytes() throws IOException
>
> Reads all remaining bytes from the input stream. This method blocks
> until all remaining bytes have been read and end of stream is
> detected
, or an exception is thrown.

end of stream is "sent" only on close(), that is why you are able to read (print) the message only after close().

a very simple solution to exchange one-line textual data would be to send messages separated by '\n' (new line) character and on the client part, read from the socket line-by-line, for example:

Server.java

import java.io.OutputStream;
import java.net.ServerSocket;
import java.net.Socket;

public class Server
{
        public static void main(String[] args) throws Exception
        {
                ServerSocket server = new ServerSocket(7788);
                Socket client = server.accept();

                OutputStream os = client.getOutputStream();
                for (int i = 0; i &lt; 5; i++) {
                        os.write(String.format(&quot;message %d\n&quot;, i).getBytes());
                        os.flush();

                        Thread.sleep(2000);
                }

                os.close();
        }
}

Client.java

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.Socket;

public class Client
{
        public static void main(String[] args) throws Exception
        {
                Socket client = new Socket(&quot;localhost&quot;, 7788);

                BufferedReader reader = new BufferedReader(new InputStreamReader(client.getInputStream()));
                String message = null;
                while ((message = reader.readLine()) != null)
                        System.out.println(message);

                reader.close();
        }
}

$ javac Server.java Client.java
$ java Server

$ java Client
message 0
message 1
message 2
message 3
message 4
$

if you run the above code, you will see that messages gets printed (received) one after the other with a 2 seconds delay and readLine() returns as soon as it read a \n (new line) character.

if this is not feasible for your use case, I think you will need a more structured protocol.

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  • 本文由 发表于 2020年9月12日 22:04:50
  • 转载请务必保留本文链接:https://go.coder-hub.com/63861127.html
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