英文:
Reverse a sentence in Java
问题
public class backwards
{
public static void main(String args[])
{
String s1 = new String("pay no attention to that man behind the curtain");
int pos = 0;
for(int i = s1.length()-1 ; i >= 0; i--)
{
if(s1.charAt(i) == ' ')
{
System.out.println(s1.substring(i+1));
s1 = s1.substring(0,i);
}
else if(i == 0)
{
System.out.println(s1);
s1 = "";
}
}
}
}
英文:
> The question for homework is the program should print the String in reverse word by word.<br>
> Your `String' should be assigned the value “pay no attention to that man behind the curtain” and should be printed as the sample output.
Getting errors compiling and been at this for 3 hours - lost!!
I must use the charAt method, the substring method and an if statement:
curtain
the
behind
man
that
to
attention
no
pay
public class backwards
{
public static void main(String args[])
{
String s1 = new String("pay no attention to that man behind the curtain");
/*int pos = s1.indexOf(' ');
while(s1.length() > 0)
{
if(pos == -1)
{
System.out.println(s1);
s1 = "";
}
else
{
System.out.println(s1.substring(0,pos));
s1 = s1.substring(pos+1);
pos = s1.indexOf(' ');
}
}*/
int pos = 0;
for(int i = s1.length()-1 ; i >= 0; i--)
{
// System.out.println("Pos: " + pos);
if(s1.charAt(i) == ' ')
{
System.out.println(s1.substring(i+1));
s1 = s1.substring(0,i);
}
else if(i == 0)
{
System.out.println(s1);
s1 = "";
}
}
}
}
答案1
得分: 3
你可以简单地这样做：
public class Main {
public static void main(String[] args) {
// 按空白字符分割
String[] arr = "pay no attention to that man behind the curtain".split("\\s+");
// 以相反顺序打印数组
for (int i = arr.length - 1; i >= 0; i--) {
System.out.println(arr[i]);
}
}
}
输出:
curtain
the
behind
man
that
to
attention
no
pay
**或者，**可以这样做：
public class Main {
public static void main(String[] args) {
String s1 = "pay no attention to that man behind the curtain";
for (int i = s1.length() - 1; i >= 0; i--) {
if (s1.charAt(i) == ' ') {
// 打印 `s1` 的最后一个单词
System.out.println(s1.substring(i + 1));
// 去掉最后一个单词并将剩余的字符串赋给 `s1`
s1 = s1.substring(0, i);
} else if (i == 0) {
// 如果 `s1` 只剩下一个单词
System.out.println(s1);
}
}
}
}
输出:
curtain
the
behind
man
that
to
attention
no
pay
英文:
You can do it simply as
public class Main {
public static void main(String[] args) {
// Split on whitespace
String[] arr = "pay no attention to that man behind the curtain".split("\\s+");
// Print the array in reverse order
for (int i = arr.length - 1; i >= 0; i--) {
System.out.println(arr[i]);
}
}
}
Output:
curtain
the
behind
man
that
to
attention
no
pay
Alternatively,
public class Main {
public static void main(String[] args) {
String s1 = "pay no attention to that man behind the curtain";
for (int i = s1.length() - 1; i >= 0; i--) {
if (s1.charAt(i) == ' ') {
// Print the last word of `s1`
System.out.println(s1.substring(i + 1));
// Drop off the last word and assign the remaining string to `s1`
s1 = s1.substring(0, i);
} else if (i == 0) {
// If `s1` has just one word remaining
System.out.println(s1);
}
}
}
}
Output:
curtain
the
behind
man
that
to
attention
no
pay
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