如何检查Java中的sleep()方法是否持有锁?

huangapple go评论80阅读模式
英文:

How to check whether sleep() method in Java holds lock or not?

问题

class MyThread extends Thread{
   public void run(){
       print();
   }
   synchronized public void print() {
       // for(int i = 0; i< )
       System.out.println("Thread : " + Thread.currentThread().getName());
       try{
           Thread.sleep(5000);}
           catch(InterruptedException e ){
               
           }
   }
}

public class MyClass {
   public static void main(String args[]) throws InterruptedException {
     
     MyThread t1 = new MyThread();
     MyThread t2 = new MyThread();
     t1.setName("A");
     t2.setName("B");
     t1.start();
     t2.start();
     t1.join();
     t2.join();
     
     System.out.println("EOM");
     
   }
}
Output of the Program -
ThreadA
ThreadB
*Immediately prints both lines*
*After 5 seconds*
EOM
>> According to my understanding, one of the threads should go into the print() and acquire lock, and only releases it after 5 seconds. However, here both threads executed immediately, and then "EOM" got printed after 5 seconds.
英文:
class MyThread extends Thread{
   public void run(){
       print();
   }
   synchronized public void print() {
       // for(int i = 0; i< )
       System.out.println("Thread : " + Thread.currentThread().getName());
       try{
           Thread.sleep(5000);}
           catch(InterruptedException e ){
               
           }
   }
}



public class MyClass {
   public static void main(String args[]) throws InterruptedException {
     
     MyThread t1 = new MyThread();
     MyThread t2 = new MyThread();
     t1.setName("A");
     t2.setName("B");
     t1.start();
     t2.start();
     t1.join();
     t2.join();
     
     System.out.println("EOM");
     
   }
}

Output of the Program -

ThreadA
ThreadB

Immediately prints both line
After 5 seconds

EOM

>>According to my understanding, one of the thread should go in print() and acquire lock and only releases it after 5 seconds but here both the threads executed immediately and then "EOM" got printed after 5 seconds.

答案1

得分: 2

synchronized 在实例方法中使用时,每个实例彼此之间不会干扰。

如果这个方法是 static 的,那么它将在不同实例之间共享。

英文:

The synchronized is in an instance method, and each instance doesn't interfere with each other.

If the method were static then it would be shared between the instances.

答案2

得分: 0

你写的代码是:

synchronized public void print() {
    ...
}

这只是一种简写方式,等价于:

public void print() {
    synchronized(this) {
        ...
    }
}

你的两个线程分别在不同的MyClass类实例上操作,因此,你的两个线程分别在不同的对象(不同的this引用)上进行同步。

当你使用synchronized(o)块时,这只会阻止两个不同的线程同时在相同的对象o上进行同步。

英文:

You wrote:

synchronized public void print() {
    ...
}

That's just a short-cut way of writing:

public void print() {
    synchronized(this) {
        ...
    }
}

Each of your two threads is operating on a different instance of your MyClass class, therefore, each of your two threads is synchronizing on a different object (different this reference).

When you use synchronized(o) blocks, that only prevents two different threads from synchronizing on the same object o at the same time.

huangapple
  • 本文由 发表于 2020年9月12日 00:02:07
  • 转载请务必保留本文链接:https://go.coder-hub.com/63850533.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定