Need help creating a method that accepts three integers and returns an integer representing the sum of only the even integer

I'm a beginner in Java and coding in general. I'm having a lot of trouble on filtering out even numbers and adding them together. I understood how to set up the scanner, and having the user input 3 different int's, but the bottom segment is where I'm completely lost. My notes in "Boolean Zen" section say to use (n1 % 2 != 0 && n2 % 2 != 0) as a test, but I can't figure out how to use it. I should repeat that I am very new, and started coding barely even 2 weeks ago. I've written:

import java.util.*;
public class U3L8Lab3
 {
   public static void main(String[] args)
   {    
      Scanner console = new Scanner(System.in);
      System.out.print("Enter 3 Intergers:");
      int num1 = console.nextInt();
      int num2 = console.nextInt();
      int num3 = console.nextInt();
      System.out.println(sumOfEvens(num1, num2, num3));
   }  
   public static int sumOfEvens(int num1, int num2, int num3)
   {
     
   } 

So you are tasked at summing the even numbers only. From what I understand, if the user had to input 3 uneven numbers, then the result should be 0 - that is the assumption I will make when providing you my answer.

Firstly, you need to determine which of the numbers are even - this is what the mod (%) functionality is for. If any number mod 2 results in 0, it means it is even. So:

public static int sumOfEvens(int num1, int num2, int num3)
   {
     int sum = 0;
     if (num1 % 2 == 0) {
       sum += num1;
     }
     if (num2 % 2 == 0) {
       sum += num2;
     }
     if (num3 % 2 == 0) {
       sum += num3;
     }
     return sum;
   } 

Not the most elegant solution, but I hope you get the gist of it.