问题

以下是您的代码翻译：

import java.util.Scanner;

public class Practice01 {

    public static void main(String[] args) {

        System.out.println("嗨！");

        Scanner scr = new Scanner(System.in);

        String response = scr.nextLine();

        if (response.equalsIgnoreCase("你好") || response.equalsIgnoreCase("嗨") || response.equalsIgnoreCase("喂")) {
            System.out.println("哦，你真有礼貌。你好，你怎么样？");
        } else {
            System.out.println("无效输入");

            String responseG;
            responseG = scr.nextLine();

            if (responseG.equalsIgnoreCase("好")) {
                System.out.println("很高兴听到这个");
            }
        }
    }
}

对于您在Java方面的问题，您在else语句后面输入"hey"、"hello"或"hi"后，程序会打印出"哦，你真有礼貌。你好，你怎么样？"，然后无法继续输入。您的问题可能是因为输入结束符的问题，导致程序无法正确读取您之后的输入。您可以尝试在输入response后添加一行 scr.nextLine(); 以清除输入缓冲区，然后再进行下一次的输入。

另外，关于您提到的将"responseG"变量和下一行代码移到if语句中的问题，您应该确保将这两行代码放在if语句的大括号内，以便它们只在满足if条件时执行。

此外，您提到在使用else if语句时出现了错误。如果您使用else if语句，确保将其与if语句对齐，并在每个else if语句后面使用花括号包裹代码块。如果您仍然遇到问题，请提供更多细节，以便我可以为您提供更准确的帮助。

public class Practice01{

	public static void main (String[] args){
		
		
		System.out.println("Hi there");

	      Scanner scr = new Scanner(System.in);

	      String response = scr.nextLine();
	      
	      
	     if (response.equalsIgnoreCase("hello") || response.equalsIgnoreCase("hi") || response.equalsIgnoreCase("hey")) {
	    	 System.out.println("Oh, well arent you well-mannered. Hello there, how are you?");}
	    	 
	     
	    	 else {
	    		 System.out.println("Invalid Input");
	    		 
	    		 
	    		 String responseG;
	    		 responseG = scr.nextLine();
	    	 
	    	 if (responseG.equalsIgnoreCase("good")) {
	    		 System.out.println("Glad to hear");
	    		 
	    	 }
	     }     
		}
	}  

答案1

得分: 0

你必须使用循环使程序保持运行。在你打印出“哦，你是个彬彬有礼的人。你好，你好吗？”之后，它终止，因为没有更多的任务要做了。

答案2

得分: 0

## 嗨，欢迎来到Stackoverflow！ ##
如果您**没有输入“hello”**、"Hello"或"hey"，您的程序将只会从键盘要求另一个输入。如果您输入了“hello”，则它将打印一行内容：
>“噢，您真有礼貌。你好，你好吗？”

然后程序将被终止...

**这就是您的代码告诉程序要做的事情**，因为您仅在else语句的主体中要求另一个输入。

根据我所见，您不想使用for循环，因为您似乎只关心一个路径，上面写着hi...你好吗？...很好...很高兴听到...但是如果您关心的话，您可以使用`while()`语句、`do..while()`语句或者`for()`语句，以便使用`scr.nextLine();`函数（它***是***一个函数）保存多个响应值，如果这样的话，您必须定义程序何时/如何停止请求输入并终止。

我认为以下代码是您尝试实现的功能，带有适当的缩进，并且没有声明不必要的变量：

```java
public class Practice01 {
    public static void main(String[] args) {

        System.out.println("Hi there");

        Scanner scr = new Scanner(System.in);
        String response = scr.nextLine();

        if (response.equalsIgnoreCase("hello") || response.equalsIgnoreCase("hi") || response.equalsIgnoreCase("hey")) {
            System.out.println("Oh, well aren't you well-mannered. Hello there, how are you?");
        } else {
            System.out.println("Invalid Input");
        }

        // 您不需要ResponseG... 您已经创建了response变量
        response = scr.nextLine();

        if (response.equalsIgnoreCase("good")) {
            System.out.println("Glad to hear");
        } else {
            System.out.println("Invalid Input");
        }
    }
}

<details>
<summary>英文:</summary>
## Hi, welcome to Stackoverflow! ##
Your program will only ask for another input from your keyboard if you **don&#39;t type &quot;hello&quot;** or &quot;Hello&quot;, or &quot;hey&quot;, you know what I mean. If you type &quot;hello&quot; then it will print a line with 
&gt;&quot;Oh, well aren&#39;t you well-mannered. Hello there, how are you?&quot;
And the program will be terminated... 
**That&#39;s what your code it&#39;s telling your program to do**, since you are only asking for another input in the else statement&#39;s body. 
As I can see you don&#39;t want to use a for loop, since you seem to only care about a path that says hi... how are you?... good... glad to hear... but if you care for it, you can use a `while()` statement or a `do..while()` or a `for()` to make it save in the variable many responses with the `scr.nextLine();` function (it ***is*** a function), in that case you have to define when/how the program is going to stop asking for input and will terminate.
----------
I believe this is what does what you were trying to do, with the proper indentation, and not declaring unnecessary variables:
public class Practice01{
public static void main (String[] args){
System.out.println(&quot;Hi there&quot;);
Scanner scr = new Scanner(System.in);
String response = scr.nextLine();
if (response.equalsIgnoreCase(&quot;hello&quot;) || response.equalsIgnoreCase(&quot;hi&quot;) || response.equalsIgnoreCase(&quot;hey&quot;)) {
System.out.println(&quot;Oh, well arent you well-mannered. Hello there, how are you?&quot;);
}     
else {
System.out.println(&quot;Invalid Input&quot;);
}
//You don&#39;t need ResponseG... you&#39;ve already created the response variable
response = scr.nextLine();
if (response.equalsIgnoreCase(&quot;good&quot;)) {
System.out.println(&quot;Glad to hear&quot;);
}
else {
System.out.println(&quot;Invalid Input&quot;);
}
}
}
</details>
# 答案3
**得分**: 0
以下是您要求的翻译内容：
所以你想要做的是将 ResponseG 的 if 语句移到你的 response if 语句中，因为这会阻止代码完成，因为你输入了正确的内容。另外在将来的项目中，为了更有条理，可以在代码开头创建变量。
```java
public class Practice01{
public static void main (String[] args){  
System.out.println("嗨，你好");
String responseG;
Scanner scr = new Scanner(System.in);
String response = scr.nextLine();
if (response.equalsIgnoreCase("hello") || 
response.equalsIgnoreCase("hi") || 
response.equalsIgnoreCase("hey")) {
System.out.println("哦，你真有礼貌。你好，你好吗？");
responseG = scr.nextLine();
if (responseG.equalsIgnoreCase("good")) {
System.out.println("很高兴听到这个。");
}
} else {
System.out.println("无效输入");
}
}  
}

    public class Practice01{
      public static void main (String[] args){  
        System.out.println("Hi there");

        String responseG;
        Scanner scr = new Scanner(System.in);
        String response = scr.nextLine();

        if (response.equalsIgnoreCase("hello") || 
            response.equalsIgnoreCase("hi") || 
            response.equalsIgnoreCase("hey")) {
          System.out.println("Oh, well arent you well-mannered. Hello there, how are you?");
             
          responseG = scr.nextLine();
             
          if (responseG.equalsIgnoreCase("good")) {
            System.out.println("Glad to hear");
          }
        } else {
          System.out.println("Invalid Input");
        }
      }  
    }