英文:
How would I write this C++ input function in Java?
问题
我正在努力弄清楚如何在Java中从控制台读取输入，以使其与以下C++代码完全相同：
Scanner scanner = new Scanner(System.in);
while (scanner.hasNextInt()) {
int input = scanner.nextInt();
}
我基本上需要一次读取一个整数，只有当用户不再输入整数时才停止。我能够逐个读取整数，但无法弄清楚如何在用户输入空行后停止执行。谢谢！
英文:
I am trying to figure out how to read input from the console in Java that would behave exactly the same as the following C++ code:
while(cin >> input)
I essentially need to keep reading the console one integer at a time, and only stop when the user enters no more integers.I am able to read integers one at a time, but cannot figure out how to get it to stop executing once the user passes an empty line. Thanks!
答案1
得分: 1
Scanner scanner = new Scanner(System.in);
// 寻找下一个整数标记并打印
// 循环整个扫描器
while (scanner.hasNext()) {
// 如果下一个是整数，则打印找到的整数
if (scanner.hasNextInt()) {
System.out.println("找到：" + scanner.nextInt());
}
// 如果没有找到整数，则打印“未找到：”和标记
System.out.println("未找到：" + scanner.next());
}
英文:
Scanner scanner = new Scanner(System.in);
// find the next int token and print it
// loop for the whole scanner
while (scanner.hasNext()) {
// if the next is a int, print found and the int
if (scanner.hasNextInt()) {
System.out.println("Found :" + scanner.nextInt());
}
// if no int is found, print "Not Found:" and the token
System.out.println("Not Found :" + scanner.next());
}
答案2
得分: 0
import java.util.*;
class TextNum {
public static void main(String[] args) {
int n;
String s;
Scanner in = new Scanner(System.in);
while (true) {
s = in.nextLine();
// 对此进行处理
System.out.println("这是：" + s + "：");
try {
n = Integer.parseInt(s);
} catch (Exception e) {
break;
}
}
}
}
英文:
You can use the Scanner nextLine() method and check for integers:
import java.util.*;
class TextNum {
public static void main(String[] args) {
int n;
String s;
Scanner in = new Scanner(System.in);
while (true) {
s = in.nextLine();
//Do something with this
System.out.println("This is :" + s + ":");
try {
n = Integer.parseInt(s);
} catch (Exception e) {
break;
}
}
}
}
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