CSS和JS在应用Servlet过滤器后不起作用。

huangapple
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英文:

CSS and JS not working after applaying servelt filter

问题

这是您提供的代码的翻译部分：

  1. 这是我第一次使用dofilter函数来对我的jsp web应用程序进行身份验证，一旦添加它，CSS和JS在任何页面上都无法工作，我一遍又一遍地搜索，但无法将解决方案应用到我的代码中。
  2. 以下是dofilter方法。
  4. @Override
  5. public void doFilter(ServletRequest req, ServletResponse resp, FilterChain chain)
  6.         throws IOException, ServletException {
  7.     HttpServletRequest request = (HttpServletRequest) req;
  8.     HttpServletResponse response = (HttpServletResponse) resp;
  10.     String servletPath = request.getServletPath();
  12.     // 存储在会话中的用户信息。
  13.     // （成功登录后）。
  14.     UserAccount loginedUser = AppUtils.getLoginedUser(request.getSession());
  16.     if (servletPath.equals("/login")) {
  17.         chain.doFilter(request, response);
  18.         return;
  19.     }
  21.     HttpServletRequest wrapRequest = request;
  23.     if (loginedUser != null) {
  24.         // 用户名
  25.         String userName = loginedUser.getUserName();
  27.         // 角色
  28.         List<String> roles = loginedUser.getRoles();
  30.         // 用userName和Roles信息包装旧请求。
  31.         wrapRequest = new UserRoleRequestWrapper(userName, roles, request);
  32.     }
  34.     // 必须登录的页面。
  35.     if (SecurityUtils.isSecurityPage(request)) {
  37.         // 如果用户未登录，
  38.         // 重定向到登录页面。
  39.         if (loginedUser == null) {
  41.             String requestUri = request.getRequestURI();
  43.             // 存储当前页面以在成功登录后重定向。
  44.             int redirectId = AppUtils.storeRedirectAfterLoginUrl(request.getSession(), requestUri);
  46.             response.sendRedirect(wrapRequest.getContextPath() + "/login?redirectId=" + redirectId);
  47.             return;
  48.         }
  50.         // 检查用户是否具有有效的角色？
  51.         boolean hasPermission = SecurityUtils.hasPermission(wrapRequest);
  52.         if (!hasPermission) {
  54.             RequestDispatcher dispatcher //
  55.                     = request.getServletContext().getRequestDispatcher("/accessDeniedView.jsp");
  57.             dispatcher.forward(request, response);
  58.             return;
  59.         }
  60.     }
  62.     chain.doFilter(wrapRequest, response);
  63. }

以下是页面中的CSS链接：

  1. <link href="vendor/fontawesome-free/css/all.min.css" rel="stylesheet" type="text/css">
  3. <link
  4.     href="https://fonts.googleapis.com/css?family=Nunito:200,200i,300,300i,400,400i,600,600i,700,700i,800,800i,900,900i"
  5.     rel="stylesheet">
英文:

it is the first time i use dofilter function for authenticating my jsp web application once added it and CSS and JS not working on any page, I made search over and over but can not apply the solutions in my code
find below dofilter method.

  1. @Override
  2. public void doFilter(ServletRequest req, ServletResponse resp, FilterChain chain)
  3. throws IOException, ServletException {
  4. HttpServletRequest request = (HttpServletRequest) req;
  5. HttpServletResponse response = (HttpServletResponse) resp;
  6. String servletPath = request.getServletPath();
  7. // User information stored in the Session.
  8. // (After successful login).
  9. UserAccount loginedUser = AppUtils.getLoginedUser(request.getSession());
  10. if (servletPath.equals(&quot;/login&quot;)) {
  11. chain.doFilter(request, response);
  12. return;
  13. }
  14. HttpServletRequest wrapRequest = request;
  15. if (loginedUser != null) {
  16. // User Name
  17. String userName = loginedUser.getUserName();
  18. // Roles
  19. List&lt;String&gt; roles = loginedUser.getRoles();
  20. // Wrap old request by a new Request with userName and Roles information.
  21. wrapRequest = new UserRoleRequestWrapper(userName, roles, request);
  22. }
  23. // Pages must be signed in.
  24. if (SecurityUtils.isSecurityPage(request)) {
  25. // If the user is not logged in,
  26. // Redirect to the login page.
  27. if (loginedUser == null) {
  28. String requestUri = request.getRequestURI();
  29. // Store the current page to redirect to after successful login.
  30. int redirectId = AppUtils.storeRedirectAfterLoginUrl(request.getSession(), requestUri);
  31. response.sendRedirect(wrapRequest.getContextPath() + &quot;/login?redirectId=&quot; + redirectId);
  32. return;
  33. }
  34. // Check if the user has a valid role?
  35. boolean hasPermission = SecurityUtils.hasPermission(wrapRequest);
  36. if (!hasPermission) {
  37. RequestDispatcher dispatcher //
  38. = request.getServletContext().getRequestDispatcher(&quot;/accessDeniedView.jsp&quot;);
  39. dispatcher.forward(request, response);
  40. return;
  41. }
  42. }
  43. chain.doFilter(wrapRequest, response);
  44. }

also find CSS link in pages

  1. &lt;link href=&quot;vendor/fontawesome-free/css/all.min.css&quot; rel=&quot;stylesheet&quot;
  2. type=&quot;text/css&quot;&gt;
  3. &lt;link
  4. href=&quot;https://fonts.googleapis.com/css?family=Nunito:200,200i,300,300i,400,400i,600,600i,700,700i,800,800i,900,900i&quot;
  5. rel=&quot;stylesheet&quot;&gt;

答案1

得分: 0

我终于在深入项目时找到了问题所在，与从Login servelt中移除"/"有关，并且应该是@WebServlet({ "/login" })。

英文:

i finally found the issue while deluging the project and it was related to remove "/" from Login servelt and to be @WebServlet({ "/login" })

huangapple
  • 本文由 发表于 2020年9月10日 00:13:17
  • 转载请务必保留本文链接：https://go.coder-hub.com/63815569.html
  • css
  • java
  • servlet-filters
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