英文:
Difference between +e vs , e in throw Exception
问题
在Java中，以下两个语句有什么区别：
throw new Exception("msg" + e);
和
throw new Exception("msg", e);
我知道它们都是可能的。它们在背后的工作方式上有什么区别，哪种做法更好？
英文:
In Java, what is the difference between following 2 statements:
throw new Exception ("msg" + e);
and
throw new Exception ("msg", e);
I know both of them are possible. Is there any difference in how they work behind the scenes and which is a better practice to use?
答案1
得分: 4
throw new Exception("msg" + e);``` 抛出一个新的`Exception`，消息是`"msg"`和`e.toString()`的连接，这个过程中丢失了`e`的堆栈跟踪。
```plaintext
throw new Exception("msg", e);``` 抛出一个新的`Exception`，消息是`"msg"`，而`e`作为原因。
<details>
<summary>英文:</summary>
`throw new Exception ("msg" + e);` throws a new `Exception` with a message that's a concatenation of `"msg"` and `e.toString()`, losing `e` stacktrace in the process.
`throw new Exception ("msg", e);` throws a new `Exception` with a message `"msg"` and `e` as the cause.
</details>
# 答案2
**得分**: 4
第一个方法创建一个新的异常，其消息是`msg`与`e`的字符串表示形式的连接。为此，将使用`e`的`toString`方法。这有效地提供了原始异常的消息，并将其与字符串`msg`连接起来。
第二个方法创建一个仅包含消息`msg`的新异常，并将原始异常添加为原因。因此，可以获得来自原始异常的更多信息，例如堆栈跟踪。
<details>
<summary>英文:</summary>
The first one creates a new exception with a message that is a string concatenation of `msg` and the string representation of `e`. For this the `toString` method of `e` will be used. This effectively gives the message of the original exception and concatenates it with the string `msg`.
The second one creates a new exception with only the message `msg` and adds the original exception as a cause. Hence, more information from the original exception is available, for example the stack trace.
</details>
# 答案3
**得分**: 0
```plaintext
throw new Exception("msg" + e);``` 抛出一个新的`Exception`，其中包含一个由`"msg"`和`e.toString()`连接而成的消息，此过程中丢失了`e`的堆栈跟踪信息。
```plaintext
throw new Exception("msg", e);``` 抛出一个新的`Exception`，消息为`"msg"`，并以`e`作为原因。
<details>
<summary>英文:</summary>
`throw new Exception ("msg" + e);` throws a new `Exception` with a message that's a concatenation of `"msg"` and `e.toString()`, losing `e` stacktrace in the process.
`throw new Exception ("msg", e);` throws a new `Exception` with a message `"msg"` and `e` as the cause.
</details>
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