英文:
How to prevent duplicates in array?
问题
我正在尝试创建一个程序，您不能使用已经被占用的相同ID添加新员工。但是，使用这段代码仍然会添加员工。您有什么建议，我如何更改我的代码？另外，数组最多可以容纳10名员工。如果需要，我将乐意提供更多信息。for（Employee employee：employeeArray）{if（employee！= null && employee.getEmployeeID（）。equals（eID））{counter = employeeArray.length - 1;System.out.println（"您的集合中已经有ID为" + eID + "的员工"）;} else if（counter < 10）{employeeArray [counter] = e_obj;counter ++;}}
英文:
I'm trying to make a program where you can't add a new employee with the same ID that is already taken. But with this code it adds the employee anyways. Any suggestions to how I can change my code?
Also the array is supposed to hold a maximum of 10 employees.
I´ll gladly provide any more information if needed.
for (Employee employee : employeeArray) {if (employee != null && employee.getEmployeeID().equals(eID)) {counter = employeeArray.length - 1;System.out.println("An employee with " + eID + " is already in your collection");} else if (counter < 10) {employeeArray= e_obj;0+网站访问量counter++;}}
答案1
得分: 2
使用HashSet替代这个。只需创建一个HashSet或者集合（set）的对象，它将不会接受任何重复的值。
英文:
Use HashSet instead of this. just create an object of HashSet or set and it will not accept any duplicate values from you.
答案2
得分: 1
如果 getEmployeeID 返回一个字符串并将其与字符串 eID 进行比较，我建议查看是否存在额外的空格或大小写敏感的问题。
if (employee != null && employee.getEmployeeID().equals(eID)) {
另外，您不需要在 if 语句中调整计数器。
counter = employeeArray.length - 1;
英文:
If getEmployeeID returns a String and compares it to a String eID I suggest seeing if there might be extra white space or a case sensitivity issue.
if (employee != null && employee.getEmployeeID().equals(eID)) {
Also, you shouldn't need to adjust the counter in the if clause.
counter = employeeArray.length - 1;
答案3
得分: 0
你可以按照以下方式操作：
// 检查员工是否已存在boolean isExisting = false;for (Employe employe : employeArr) {if (employe != null && employe.getEmployeID() != null && employe.getEmployeID().equals(eID)) {isExisting = true;break;}}if (!isExisting) {// 添加员工的现有逻辑}
英文:
You can do it as follows:
// Check if the employee already existsboolean isExisting = false;for (Employe employe : employeArr) {if (employe != null && employe.getEmployeID() != null && employe.getEmployeID().equals(eID)) {isExisting = true;break;}}if(!isExisting) {// Your existing logic to add the employee}
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