英文:
It is not going inside the first loop and only printing I am outside loop only
问题
以下是您提供的代码的翻译部分：
package string_pattern;
public class Naive {
public static void main(String[] args)
{
String pattern = "This is a text book";
String text = "text";
child obj = new child();
obj.search(pattern, text);
}
}
class child {
public void search(String pat, String text)
{
int m, n;
m = pat.length();
n = text.length();
System.out.println("我在循环外部");
for (int i = 0; i <= (n - m); i++)
{
int j;
System.out.println("我在第一个循环内部");
for (j = 0; j < m; j++)
{
if (text.charAt(i + j) != pat.charAt(j))
{
System.out.println("在这里");
break;
}
if (j == m)
System.out.println("在位置找到模式" + i);
}
}
}
}
请注意，我已根据您的要求仅提供代码的翻译部分，去除了其他内容。如果您需要进一步的帮助，请随时询问。
英文:
The below code is not giving any error. After debugging i found it is not going inside the first loop.
package string_pattern;
public class Naive {
public static void main(String[] args)
{
String pattern="This is a text book";
String text="text";
child obj=new child();
obj.search(pattern, text);
}
}
class child{
public void search(String pat,String text)
{
int m,n;
m=pat.length();
n=text.length();
System.out.println("i am outside loop");
for(int i=0; i<= (n-m); i++)
{
int j;
System.out.println("i am inside first loop");
for(j=0;j<m;j++)
{
if(text.charAt(i+j) != pat.charAt(j))
{
System.out.println("OVER HERE");
break;
}
if(j==m)
System.out.println("pattern found at pos" + i);
}
}
}
}
答案1
得分: 1
你需要执行以下操作：
m = pat.length();
n = text.length();
问题在于`text`的长度为4，而`pat`较长。因此，当你像这样循环时 -> `for(int i=0; i<= (n-m); i++)`，你最终得到一个负数。因为0大于任何负数，所以你永远不会进入循环。
英文:
You do the following:
m=pat.length();
n=text.length();
The problem is that text has a length of 4, while pat is longer. So when you do the loop like this -> for(int i=0; i<= (n-m); i++), you end up with a negative number. Since 0 is greater than any negative number you never enter the loop.
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