英文:
Convert String to Map without regex
问题
我有一个返回以下格式字符串的服务器：
{"success":true,"visible":false,"data":{"ref":"asfdasfsadfaeweatsagsdfsad","userRef":"asdfsadfsa","accountType":"REAL","balance":43},"code":"2200","msg":null,"msgRef":null,"successAndNotNull":true,"failedOrNull":false,"failed":false,"failedAndNull":false}
然后，我通过以下方式提取data：
val jsonObj: Any! = JSONObject(serverResponse.toString()).get("data").toString()
然后得到以下字符串：
"{"ref":"safdasfdwaer","userRef":"fdgsgdsgdsfg","accountType":"REAL","balance":43}"
有没有一种有效的方法将这些值提取到一个HashMap中，以:左边的内容作为键，以:右边的内容作为值？
我已经在这里看到了答案（https://stackoverflow.com/questions/17691304/convert-string-to-map），但是我不能使用正则表达式。
英文:
I have a server that returns a String of this format:
{"success":true,"visible":false,"data":{"ref":"asfdasfsadfaeweatsagsdfsad","userRef":"asdfsadfsa","accountType":"REAL",balance":43},"code":"2200","msg":null,"msgRef":null,"successAndNotNull":true,"failedOrNull":false,"failed":false,"failedAndNull":false}`
Then I extract the data by doing this:
val jsonObj : Any! = JSONObject(serverResponse.toString()).get("data").toString()
and I end up with this String:
"{"ref":"safdasfdwaer","userRef":"fdgsgdsgdsfg","accountType":"REAL","balance":43}"
Is there an efficient way to extract the the values into a HashMap with key what is on the left of ":" and value what is on the right of ":"?
I have already seen the answer here (https://stackoverflow.com/questions/17691304/convert-string-to-map) but I am not allowed to to use regex
答案1
得分: 0
问题在于您通过显式写入类型将您的 jsonObj 强制转换为 Any
val jsonObj: Any!
由于您的方法实际上返回一个字符串（因为它以 toString() 结尾）
JSONObject(serverResponse.toString()).get("data").toString()
只需编写
val jsonObjStr = JSONObject(serverResponse.toString()).get("data").toString()
然后使用我们在评论中提出的答案中的解决方案。
val result: Map<String, Any> =ObjectMapper().readValue(jsonObjStr, HashMap::class.java);
英文:
The problem is that you force your jsonObj to be Any by writing type explicitly
val jsonObj : Any!
Since your method actually returns String (as it ends with toString())
JSONObject(serverResponse.toString()).get("data").toString()
Just write
val jsonObjStr = JSONObject(serverResponse.toString()).get("data").toString()
And then use solution from the answer we proposed in the comments.
val result: Map<String, Any> =ObjectMapper().readValue(jsonObjStr, HashMap::class.java);
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