英文:
how to add values in an array from last value to first
问题
如何将arrNumbers中超过6的值相加，并将其添加到一个新数组中，新数组从最后一个值开始，以第一个值结束。
这是我编写的代码，但输出不正确。
int[] arrNumbers = new int[] { 1, 2, 3, 4, 5, 6, 1, 2 };
int[] newArrNumbers = new int[6];
for (int i = arrNumbers.length - 1; i >= 0; i--) {
if (arrNumbers[i] > 6) {
newArrNumbers[5 - (arrNumbers.length - 1 - i)] += arrNumbers[i];
}
}
实际输出：
newArrNumbers = [1, 2, 3, 4, 7, 7]
英文:
How can I add the values in the arrNumbers that exceed 6 to add to a new array starting from the last value and ending at the first.
This is what I have written, but does not produce the right output.
int[] arrNumbers = new int[] { 1, 2, 3, 4, 5, 6, 1, 2 };
int[] newArrNumbers = new int[6];
for(int i = 0; i < arrNumbers.length ; i++){
newArrNumbers[i % 6] += arrNumbers[i];
}
The actual output:
newArrNumbers = [2, 4, 3, 4, 5, 6]
However, I want the output to ADD to the LAST VALUE in the arrNumbers, going from right to left, not left to right. So result should be:
newArrNumbers = [1, 2, 3, 4, 7, 7]
答案1
得分: 1
尝试一下。
int[] arrNumbers = new int[] { 1, 2, 3, 4, 5, 6, 1, 2 };
int[] newArrNumbers = new int[6];
for (int i = 0; i < arrNumbers.length; i++) {
newArrNumbers[i < 6 ? i : (6 - (i % 6) - 1)] += arrNumbers[i];
}
System.out.println(Arrays.toString(newArrNumbers));
输出：
[1, 2, 3, 4, 7, 7]
英文:
Try this.
int[] arrNumbers = new int[] { 1, 2, 3, 4, 5, 6, 1, 2 };
int[] newArrNumbers = new int[6];
for(int i = 0; i < arrNumbers.length ; i++){
newArrNumbers[i < 6 ? i : (6 - (i % 6) - 1)] += arrNumbers[i];
}
System.out.println(Arrays.toString(newArrNumbers));
output:
[1, 2, 3, 4, 7, 7]
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