Java Format string to C#

Don't understand Java's syntax. How to convert: "%6d %7.1f %5.1f" to C# equivalent ?

I keep getting this print out in C#: %6d %7.1f %5.1f

Tried:

"{0:d6} {7:1f} {5:1f}"

But, ran into an exception.

Exception:

Unhandled Exception: System.FormatException: Index (zero based) must be greater than or equal to zero and less than the size of the argument list.
   at System.Text.StringBuilder.AppendFormatHelper(IFormatProvider provider, String format, ParamsArray args)
   at System.String.FormatHelper(IFormatProvider provider, String format, ParamsArray args)
   at System.String.Format(String format, Object arg0, Object arg1, Object arg2)
   at experiment.Main(String[] args)

The Java code:

String.format("%6d %7.1f %5.1f", int, double, double/double);

It's obvious what values will be generated based on variable data types.

EDIT: I just looked at, https://stackoverflow.com/questions/17635617/convert-this-line-of-java-code-to-c-sharp-code

C#

String.Format("{0:x2}", arrayOfByte[i]);

Java

String.format("%02x", arrayOfByte[i]);

PLEASE. PLEASE. PLEASE. DO not close this. Kindly. Please.

NOTE: Completely rewrote my original answer based on a (hopefully) better understanding of the Java format specifiers.

Based on my (Google-limited understanding), %6d, %7.1f and %5.1f correspond to the following:

• An integer with up to 6 characters, padded if less than 6.
• A float with up to 7 characters (including the decimal point and decimal portion) with a precision of 1.
• A float with up to 5 characters (including the decimal point and decimal portion) with a precision of 1.

You can accomplish this with C#'s String.Format, like this:

var newString = String.Format("{0,6:d} {1,7:f1}, {2,5:f1}", 605, 20.5, 8.22);

This will result in the following string:

"   605    20.5  8.22"

The first digit in each placeholder group (defined by { and }) corresponds to the argument passed in after the string:

• 0 = 605
• 1 = 20.5
• 2 = 8.22

The second digit, after the , refers to the length of the string (including decimal points and decimal portions).

• 6 = 6 characters for the integer
• 7 = 7 characters for the float
• 5 = 5 characters for the float

The letters and numbers after the : are the format specifiers.

• d = integer
• f1 = floating with a precision of 1.

Which produces the string above, as follows:

• {0,6:d} turns 605 into " 605" (3 leading spaces due to the 6 before the
• {1,7:f1} turns 20.5 into " 20.5" (3 leading spaces due to the 7 before the
• {2,5:f1} turns 8.22 into " 8.2" (1 leading space due to the 5 before the : and 1 decimal number due to the precision).

As I said earlier, check String.Format and Standard Numeric Format Strings for more information.

Starting from C# 6. you can use interpolation.
For your case you may wanted to try the following:

string formattedString = $"{0:d6} {7.1:f} {5.1:f}";

before C# 6 you can try the following:

string formattedString = String.Format("{0:d6} {1:f} {2:f}", 0, 7.1, 5.1);