英文:
How do get the code to respond if user dose not type anything and just presses enter?
问题
以下是您的代码的翻译部分：
import java.util.Scanner;
class Main {
static Scanner name = new Scanner(System.in);
public static void main(String[] args) {
System.out.println("请输入您的名字：");
String a = name.nextLine();
String b = a.substring(0, 1).toUpperCase() + a.substring(1);
String c = a.trim();
if (c.length() != 0) {
if (a.contains(" ")) {
System.out.println("您在名字中输入了空格。 : (");
} else {
System.out.println(b + " 是一个很好的名字！ : )");
}
} else {
System.out.println("这不是一个名字！ : (");
}
}
}
英文:
I want my code to respond if the user only presses enter and doesn't type anything else. I use .trim to react to only putting in spaces but, it gives me an error when I just hit enter as the input. Here is what I have so far:
import java.util.Scanner;
class Main {
static Scanner name = new Scanner(System.in);
public static void main(String[] args) {
System.out.println("What is your first name?");
String a = name.nextLine();
String b = a.substring(0, 1).toUpperCase() + a.substring(1);
String c = a.trim();
if (c.length() != 0) {
if (a.contains(" ")) {
System.out.println("You put space in your name. : (");
} else {
System.out.println(b + " is a nice name! : )");
}
} else {
System.out.println("Thats not a name! : (");
}
}
}
答案1
得分: 1
try (Scanner scan = new Scanner(System.in)) {
System.out.println("What is your first name?");
String str = scan.nextLine().trim();
if (str.isEmpty())
System.err.println("You entered an empty name");
else if (str.contains(" "))
System.err.println("You put space in your name.");
else {
String name = Character.toUpperCase(str.charAt(0)) + str.substring(1);
System.out.println('\'' + name + "' is a nice name!");
}
}
英文:
try (Scanner scan = new Scanner(System.in)) {
System.out.println("What is your first name?");
String str = scan.nextLine().trim();
if (str.isEmpty())
System.err.println("You entered an empty name");
else if (str.contains(" "))
System.err.println("You put space in your name.");
else {
String name = Character.toUpperCase(str.charAt(0)) + str.substring(1);
System.out.println('\'' + name + "' is a nice name!");
}
}
答案2
得分: 0
以下是翻译的内容：
我认为这可能是你想要的。此外，我还突出了一些最佳实践。
class Main {
private static Scanner scanner = new Scanner(System.in); // 点0 - 使用访问修饰符！
public static void main(String[] args) {
System.out.println("What is your first name?");
String name = ""; // 点1 - 初始化变量以避免空指针异常
// 点2 - 始终检查是否有内容可从扫描仪读取
if (scanner.hasNextLine()) {
name = scanner.nextLine();
}
// 点3 - 您可以在原地使用方法，而不是使用堆栈变量
if (!name.isEmpty()) {
if (name.contains(" ")) {
System.out.println("You put space in your name. : (");
} else {
// 点4 - 您可以省去额外的变量
System.out.println(capitalize(name) + " is a nice name! : )");
}
} else {
System.out.println("That's not a name! : (");
}
scanner.close(); // 点5 - 清理您的资源
}
// 点6 - 简洁的方法使代码更易读
private static String capitalize(String str) {
return str.substring(0, 1).toUpperCase() + str.substring(1);
}
}
你可以查阅更多关于 Scanner 的信息。
英文:
I think this is probably what you want. Furthermore, I've also highlighted a few best practices.
class Main {
private static Scanner scanner = new Scanner(System.in); // Point 0 - Use access modifiers!
public static void main(String[] args) {
System.out.println("What is your first name?");
String name = ""; // Point 1 - Initialize your variables to avoid NullPointerException
// Point 2 - Always check if there is something to read from scanner
if (scanner.hasNextLine()) {
name = scanner.nextLine();
}
// Point 3 - You can methods in place instead of stack variables
if (!name.isEmpty()) {
if(name.contains(" ")) {
System.out.println("You put space in your name. : (");
} else {
// Point 4 - You can do away with extra variables
System.out.println(capitalize(name) + " is a nice name! : )");
}
} else {
System.out.println("That's not a name! : (");
}
scanner.close(); // Point 5 - Clean up your resources
}
// Point 6 - Concise methods makes code more readable
private static String capitalize(String str) {
return str.substring(0, 1).toUpperCase() + str.substring(1);
}
}
You can look up more about Scanner.
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