英文:
Multiple filters on a Path i.e. file
问题
我对以下代码有一个问题：```javaimport java.io.*import java.nio.*import org.springframework.core.io.FileSystemResource;import org.springframework.core.io.Resource;public static void FileReader {String filePath = "C:\\Downloads\\";Stream<Path> walk = Files.walk(Paths.get(filePath));List<Resource> result = walk.map(file -> file.toString()).filter(file -> file.endsWith(".json")).map(file -> new FileSystemResource(file)).collect(Collectors.toList());walk.close();}
你是否可以在文件上有多个过滤器，比如一个用于文件是否以 .zip 结尾？
<details><summary>英文:</summary>I have a question on the following code:```javaimport java.io.*import java.nio.*import org.springframework.core.io.FileSystemResource;import org.springframework.core.io.Resource;public static void FileReader {String filePath = "C:\Downloads\"";Stream<Path> walk = Files.walk(Paths.get(filePath));List<Resource> result = walk.map(file -> file.toString()).filter(file -> file.endsWith(".json")).map(file -> new FileSystemResource(file)).collect(Collectors.toList());walk.close()}
Can you have multiple filters on file, such as one for if the file ends in .zip?
答案1
得分: 1
总之 - 是的。
首先，您的筛选器可以包含多个条件，这些条件可以用一些逻辑运算符连接在一起，例如：
List<Resource> result = walk.map(file -> file.toString()).filter(file -> file.endsWith(".json") || file.endsWith(".zip")).map(file -> new FileSystemResource(file)).collect(Collectors.toList());
其次，您可以有多个filter调用，并且可以在终止调用之前的任何地方混合它们，例如：
List<Resource> result = walk.map(file -> file.toString()).filter(file -> file.endsWith(".json")).map(file -> new FileSystemResource(file)).filter(f -> f != null) // 或者更有意义的条件....collect(Collectors.toList());
英文:
In a word - yes.
First, your filter could contain several conditions joined together with some logical operator, e.g.:
List<Resource> result = walk.map(file -> file.toString()).filter(file -> file.endsWith(".json") || file.endsWith(".zip").map(file -> new FileSystemResource(file)).collect(Collectors.toList());
Second, you could have multiple filter calls and you can mix them up anywhere before the terminating call, e.g.:
List<Resource> result = walk.map(file -> file.toString()).filter(file -> file.endsWith(".json")).map(file -> new FileSystemResource(file)).filter(f -> f != null) // Or something more meaningful....collect(Collectors.toList());
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