多个筛选器在路径上,即文件。

huangapple go评论83阅读模式
英文:

Multiple filters on a Path i.e. file

问题

我对以下代码有一个问题

```java
import java.io.*
import java.nio.*
import org.springframework.core.io.FileSystemResource;
import org.springframework.core.io.Resource;

public static void FileReader { 
    String filePath = "C:\\Downloads\\";
    Stream<Path> walk = Files.walk(Paths.get(filePath));
    List<Resource> result = walk
                           .map(file -> file.toString())
                           .filter(file -> file.endsWith(".json"))
                           .map(file -> new FileSystemResource(file))
                           .collect(Collectors.toList());
    walk.close();
}

你是否可以在文件上有多个过滤器,比如一个用于文件是否以 .zip 结尾?


<details>
<summary>英文:</summary>

I have a question on the following code:

```java
import java.io.*
import java.nio.*
import org.springframework.core.io.FileSystemResource;
import org.springframework.core.io.Resource;

public static void FileReader { 
    String filePath = &quot;C:\Downloads\&quot;&quot;;
    Stream&lt;Path&gt; walk = Files.walk(Paths.get(filePath));
    List&lt;Resource&gt; result = walk
                           .map(file -&gt; file.toString())
                           .filter(file -&gt; file.endsWith(&quot;.json&quot;))
                           .map(file -&gt; new FileSystemResource(file))
                           .collect(Collectors.toList());
    walk.close()
}

Can you have multiple filters on file, such as one for if the file ends in .zip?

答案1

得分: 1

总之 - 是的。

首先,您的筛选器可以包含多个条件,这些条件可以用一些逻辑运算符连接在一起,例如:

List<Resource> result = walk
                           .map(file -> file.toString())
                           .filter(file -> file.endsWith(".json") || file.endsWith(".zip"))
                           .map(file -> new FileSystemResource(file))
                           .collect(Collectors.toList());

其次,您可以有多个filter调用,并且可以在终止调用之前的任何地方混合它们,例如:

List<Resource> result = walk
                           .map(file -> file.toString())
                           .filter(file -> file.endsWith(".json"))
                           .map(file -> new FileSystemResource(file))
                           .filter(f -> f != null) // 或者更有意义的条件...
                           .collect(Collectors.toList());
英文:

In a word - yes.

First, your filter could contain several conditions joined together with some logical operator, e.g.:

List&lt;Resource&gt; result = walk
                       .map(file -&gt; file.toString())
                       .filter(file -&gt; file.endsWith(&quot;.json&quot;) || file.endsWith(&quot;.zip&quot;)
                       .map(file -&gt; new FileSystemResource(file))
                       .collect(Collectors.toList());

Second, you could have multiple filter calls and you can mix them up anywhere before the terminating call, e.g.:

List&lt;Resource&gt; result = walk
                       .map(file -&gt; file.toString())
                       .filter(file -&gt; file.endsWith(&quot;.json&quot;))
                       .map(file -&gt; new FileSystemResource(file))
                       .filter(f -&gt; f != null) // Or something more meaningful...
                       .collect(Collectors.toList());

huangapple
  • 本文由 发表于 2020年9月1日 07:10:14
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确定