英文:
Get Value and pass as parameter to function in Java
问题
ResponseEntity<String> respEntity = null;
try {
respEntity = getConfiguredRestTemplate().exchange(uri.toString()
, HttpMethod.GET
, entity
, new ParameterizedTypeReference<String>() {
});
log.debug("URL to retrieve a document : {}", respEntity.getBody());
}
// The respEntity.getBody() returns {"url":"https://aps-fst"}
// I want to send only the value - https://aps-fst as parameter to a function
// to download the content in the URL. How to extract only the URL value and
// pass it as parameter of type URL / String ?
英文:
ResponseEntity<String> respEntity = null;
try {
respEntity = getConfiguredRestTemplate().exchange(uri.toString()
, HttpMethod.GET
, entity
, new ParameterizedTypeReference<String>() {
});
log.debug("URL to retrieve a document : {}", respEntity.getBody());
}
The respEntity.getBody() returns {"url":"https://aps-fst"}
I want to send only the value - https://aps-fst as parameter to a function to download the content in the URL. How to extract only the URL value and pass it as parameter of type URL / String ?
答案1
得分: 0
你可以使用 jackson 中的 ObjectMapper，将响应体转换为一个映射（map），从中可以取出 url 的值。你可以在这里找到一个示例：链接。
英文:
You can use ObjectMapper from jackson and have the response body transformed into a map from which you can take the url value. You can find an example here.
答案2
得分: -1
String jsonString = respEntity.getBody();
JSONObject obj = new JSONObject(jsonString);
String s3urlvalue = obj.getString("url");
log.debug("S3 URL to retrieve a document : {}", s3urlvalue);
我能够通过上述代码获得值。
英文:
String jsonString = respEntity.getBody();
JSONObject obj = new JSONObject(jsonString);
String s3urlvalue = obj.getString("url");
log.debug("S3 URL to retrieve a document : {} ", s3urlvalue);
I am able to get value with above code
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