获取Android中的字符串，逐行编程获取。

huangapple
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英文:

Get string line by line android programmatically

问题

以下是您要翻译的部分：

原文：

I have this code but the problem is that this continually showing toast of each string line when I pressed my desired button.

Like this:

Clicked the button once:

Toast shows continually:

A

B

C

What I want is to get string from a single line once I click the button.

Like this:

EditText value:
A

B

C

Result first click:

A only

Result second click:

B only

Result third click:

C only

Like that

Btw this is the code I use:

  1. Button checkButton = (Button) findViewById(R.id.check_Button);
  2. checkButton.setOnClickListener(new View.OnClickListener() {
  3.     public void onClick(View v) {
  4.         
  5.         EditText editBox = (EditText) findViewById(R.id.edit_Text);
  6.         String items = editBox.getText().toString();
  7.         Scanner scanner = new Scanner(items);
  8.         while (scanner.hasNextLine()) {
  9.             String line = scanner.nextLine();
  10.             Toast.makeText(getApplicationContext(), line, Toast.LENGTH_SHORT).show();
  11.         }
  12.         scanner.close();
  13.         
  14.     }
  15. }
  16. );

I know it's hard to understand but please bare with me.

翻译：

我有这段代码，但问题是每当我按下所需按钮时，它会持续显示每个字符串行的提示。

像这样：

单击按钮一次：

提示不断显示：

A

B

C

我想要的是，一旦我点击按钮，就从单行获取字符串。

像这样：

EditText 值：
A

B

C

第一次点击结果：

仅 A

第二次点击结果：

仅 B

第三次点击结果：

仅 C

就像这样

顺便说一下，这是我使用的代码：

  1. Button checkButton = (Button) findViewById(R.id.check_Button);
  2. checkButton.setOnClickListener(new View.OnClickListener() {
  3.     public void onClick(View v) {
  4.         
  5.         EditText editBox = (EditText) findViewById(R.id.edit_Text);
  6.         String items = editBox.getText().toString();
  7.         Scanner scanner = new Scanner(items);
  8.         while (scanner.hasNextLine()) {
  9.             String line = scanner.nextLine();
  10.             Toast.makeText(getApplicationContext(), line, Toast.LENGTH_SHORT).show();
  11.         }
  12.         scanner.close();
  13.         
  14.     }
  15. }
  16. );

我知道这很难理解，但请谅解。

英文:

I have this code but the problem is that this continually showing toast of each string line when I pressed my desired button.

Like this:

Clicked the button once:

Toast shows continually:

A

B

C

What I want is to get string from a single line once I click the button.

Like this:

EditText value:
A

B

C

Result first click:

A only

Result second click:

B only

Result third click:

C only

Like that

Btw this is the code I use:

  1. Button checkButton = (Button) findViewById(R.id.check_Button);
  2. 		checkButton.setOnClickListener(new View.OnClickListener() {
  3. 				public void onClick(View v) {
  4. 					
  5. 					EditText editBox = (EditText) findViewById(R.id.edit_Text);
  6. 					String items = editBox.getText().toString();
  7. 					Scanner scanner = new Scanner(items);
  8. 					while (scanner.hasNextLine()) {
  9. 						String line = scanner.nextLine();
  10. 						Toast.makeText(getApplicationContext(), line, Toast.LENGTH_SHORT).show();
  11. 					}
  12. 					scanner.close();
  13. 					
  14. 				}
  15. 			}
  16. 		);

I know it's hard to understand but please bare with me.

答案1

得分: 0

我认为你可以采用这样的方法。

  1. int clicks = 0;
  2. Button checkButton = (Button) findViewById(R.id.check_Button);
  3. checkButton.setOnClickListener(new View.OnClickListener() {
  4.     public void onClick(View v) {
  5.         EditText editBox = (EditText) findViewById(R.id.edit_Text);
  6.         String items = editBox.getText().toString();
  7.         if (i == 0) {
  8.             Toast.makeText(getApplicationContext(), items, Toast.LENGTH_LONG).show();
  9.             i++;
  10.             editBox.setText("");
  11.         } else if (i == 1) {
  12.             Toast.makeText(getApplicationContext(), items, Toast.LENGTH_LONG).show();
  13.             i++;
  14.             editBox.setText("");
  15.         } else if (i == 2) {
  16.             Toast.makeText(getApplicationContext(), items, Toast.LENGTH_LONG).show();
  17.             i = 0;
  18.         }
  19.     }
  20. });

当值在单击按钮后重置时，只需在editText中输入一个值。

英文:

I think you can go for an approach like this.

  1.     int clicks = 0;
  2.     Button checkButton = (Button) findViewById(R.id.check_Button);
  3.     checkButton.setOnClickListener(new View.OnClickListener() {
  4.          public void onClick(View v) {
  5.          EditText editBox = (EditText) findViewById(R.id.edit_Text);
  6.          String items = editBox.getText().toString();
  7.          if (i == 0) {  
  8.             Toast.makeText(getApplicationContext(), items , Toast.LENGTH_LONG).show();  
  9.             i++;  
  10.             editBox.setText("");
  11.          } else if (i == 1) {  
  12.            Toast.makeText(getApplicationContext(), items , Toast.LENGTH_LONG).show();  
  13.            i++; 
  14.            editBox.setText("");
  15.          } else if (i==2) {
  16.            Toast.makeText(getApplicationContext(), items , Toast.LENGTH_LONG).show();  
  17.            i = 0;
  18.          }  
  19.   } 
  20.     
  21. }

Just enter a value in the editText when the value is reset after a single button click.

答案2

得分: 0

  1. int position = 0;
  2. EditText editText = findViewById(R.id.editText);
  3. editText.addTextChangedListener(new TextWatcher() {
  4.     public void afterTextChanged(Editable editable) {
  5.         
  6.        
  7.     }
  9.     public void beforeTextChanged(CharSequence charSequence, int i, int i2, int i3) {
  10.     }
  12.     public void onTextChanged(CharSequence charSequence, int i, int i2, int i3) {
  13.        if(charSequence.length()<=0)
  14. 	   {
  15. 			position = -1;
  16. 	   }
  17. 	   else{
  18. 			position = 0;
  19. 	   }
  20.        
  21.     }
  22. });
  23. Button button = findViewById(R.id.button);
  24. button.setOnClickListener(new View.OnClickListener(){
  25.     public void onClick(View v){
  26.         int length = editText.getText().length();
  27.         if(position == -1){
  28.             Toast.makeText(getApplicationContext(),"Nothing in EditText box",Toast.LENGTH_LONG).show();
  29.             return;
  30.         }
  31.         if(position == length){
  32.             position = 0;    
  33.         }
  34.         
  35.         Toast.makeText(getApplicationContext(),String.valueOf(editText.getText().charAt(position)),Toast.LENGTH_LONG).show();
  36.         position++;
  37.         
  38.     }
  39. });
英文: 
  1. int position=0;
  2. EditText editText=findViewById(R.id.editText);
  3. editText.addTextChangedListener(new TextWatcher() {
  4.         public void afterTextChanged(Editable editable) {
  5.             
  6.            
  7.         }
  9.         public void beforeTextChanged(CharSequence charSequence, int i, int i2, int i3) {
  10.         }
  12.         public void onTextChanged(CharSequence charSequence, int i, int i2, int i3) {
  13.            if(charSequence.length()&lt;=0)
  14. 		   {
  15. 				position=-1;
  16. 		   }
  17. 		   else{
  18. 				position=0;
  19. 		   }
  20. 		   
  21.         }
  22.     });
  23. Button button=findViewById(R.id.button);
  24. button.setOnClickListener(new View.OnClickListener(){
  25. 	public void onClick(View v){
  26. 		int length=editText.getText().length();
  27. 		if(position==-1){
  28. 			Toast.makeText(getApplicationContext(),&quot;Nothing in EditText box&quot;,Toast.LENGTH_LONG).show();
  29. 			return;
  30. 		}
  31. 		if(position==length){
  32. 			position=0;	
  33. 		}
  34. 		
  35. 			Toast.makeText(getApplicationContext(),editText.getText().charAt(position),Toast.LENGTH_LONG).show();
  36. 			position++;
  37. 		
  38. 	}
  39. });

huangapple
  • 本文由 发表于 2020年8月28日 13:48:45
  • 转载请务必保留本文链接：https://go.coder-hub.com/63628139.html
  • android
  • java
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