JPA:检查集合中是否存在具有属性的成员

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英文:

JPA: Check if Collection has member with property

问题

在我的软件中,我有一个实体(我们称其为Member),其中包含另一个实体的集合(我们称其为State)。我需要编写的查询应该返回所有没有具有特定属性值(例如5)的State的成员(Member)。

以下是实体的相关部分:

public class Member {
    @JoinColumn(name = "MEMBER_ID")
    @OneToMany
    private List<State> states;

    @Column
    private String name;
}

public class State {
    @Column
    private int property;
}

请注意,MemberState之间没有双向映射,映射是在关系的非拥有方(Member)上声明的。在SQL中,我会创建如下查询:

SELECT m.name
FROM Member m
WHERE NOT EXISTS (
    SELECT *
    FROM State s
    WHERE
        m.id = s.member_id
        AND s.property = 5
);

但是我不知道如何在JPQL中实现相同的功能,而不必在关系的拥有方上进行映射。是否有任何方法可以实现这一点,而不必费心去处理双向映射呢?

英文:

In my software, I have an entity (let's call it Member) with a collection of another entity (let's call it State). The query I need to write should return all members who have no State with a specific property value (e. g. 5).

Here are the relevant parts of the entities:

public class Member {
    @JoinColumn(name = &quot;MEMBER_ID&quot;)
    @OneToMany
    private List&lt;State&gt; states;

    @Column
    private String name;
}

public class State {
    @Column
    private int property;
}

Note that there is no bidirectional mapping between Member and State, the mapping is declared on the non-owning side of the relation (Member). In SQL I would create a query like this:

<!-- language: lang-sql -->

SELECT m.name
FROM Member m
WHERE NOT EXISTS (
    SELECT *
    FROM State s
    WHERE
        m.id = s.member_id
        AND s.property = 5
);

But I don't know of any way to achieve the same thing in JPQL without having a mapping on the owning side of the relation. Is there any way to achieve this without having to bother with bidirectional mappings?

答案1

得分: 5

JPA允许在子查询的FROM子句中使用集合引用,因此您可以使用以下内容:

SELECT m.name 
FROM Member m 
WHERE NOT EXISTS(
    SELECT 1 
    FROM m.states s 
    WHERE s.property = 5
)

这将生成您所需的准确SQL语句。

英文:

JPA allows to use collection references in subquery from clauses, so you can use this:

SELECT m.name 
FROM Member m 
WHERE NOT EXISTS(
    SELECT 1 
    FROM m.states s 
    WHERE s.property = 5
)

This will produce exactly the SQL you want.

答案2

得分: 0

尝试类似这样的内容:

选择 m.name 从 Member m 其中不存在 (
    从 Member m1 加入 m1.states s 其中 s.property = 5
)

或者

选择 m.name 从 Member m 其中 m.id 不在 (
    选择 m1.id 从 Member m1 加入 m1.states s 其中 s.property = 5
)
英文:

Try something like this

select m.name from Member m where not exists(
    from Member m1 join m1.states s where s.property = 5
)

or

select m.name from Member m where m.id not in(
    select m1.id from Member m1 join m1.states s where s.property = 5
)

答案3

得分: 0

你可以像这样编写本地查询:

选择名称从成员中,其中成员ID不在(选择ID从状态中,其中属性=5)

英文:

you can write native query like this

> select name from Member where member_id not in ( select id from states
> where property = 5)

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  • 本文由 发表于 2020年8月26日 19:34:54
  • 转载请务必保留本文链接:https://go.coder-hub.com/63596784.html
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