将百分比值四舍五入为最接近的数字。

huangapple go评论69阅读模式
英文:

Round percentage value to nearest number

问题

import java.math.RoundingMode;
import java.text.NumberFormat;

public class RoundingModeExample {
    public static void main(String[] args) {
        System.out.println(formatPercentage("0.0195") + "(expected 2.0%)");
        System.out.println(formatPercentage("0.0401") + "(expected 4.0%)");
    }

    private static String formatPercentage(String number) {
        String formattedValue = "";
        NumberFormat numberFormat = NumberFormat.getPercentInstance();
        numberFormat.setMinimumFractionDigits(1);
        numberFormat.setRoundingMode(RoundingMode.HALF_UP);
        try {
            formattedValue = numberFormat.format(Double.valueOf(number));
        } catch (NumberFormatException e) {
            formattedValue = number;
        }
        return formattedValue;
    }
}

以上程序的输出:

1.9%(expected 2.0%)

4.0%(expected 4.0%)

英文:

I wanted to convert a number which is in string format to a percentage value with one decimal point. Below is my sample input and expected output.

Expected results:

"0.0195" => "2.0%"

"0.0401" => "4.0%"

I know this may be a simple question but I am not able to find the exact solution for this using java APIs, I tried all the rounding modes present under RoundingMode enum, but no rounding mode gives my expected result. Could you please help, I may be missing something.


import java.math.RoundingMode;
import java.text.NumberFormat;

public class RoundingModeExample {
    public static void main(String[] args) {
        System.out.println(formatPercentage("0.0195") + "(expected 2.0%)");
        System.out.println(formatPercentage("0.0401") + "(expected 4.0%)");
    }

    private static String formatPercentage(String number) {
        String formattedValue = "";
        NumberFormat numberFormat = NumberFormat.getPercentInstance();
        numberFormat.setMinimumFractionDigits(1);
        numberFormat.setRoundingMode(RoundingMode.HALF_UP);
        try {
            formattedValue = numberFormat.format(Double.valueOf(number));
        } catch (NumberFormatException e) {
            formattedValue = number;
        }
        return formattedValue;
    }


}

Output of the above program:

1.9%(expected 2.0%)

4.0%(expected 4.0%)

答案1

得分: 6

问题在于 0.0195 存在一个问题,即没有一个double精度的数字能够在数学上完全等于它。当你在程序源代码中编写 0.0195,或将字符串“0.0195”解析为双精度数时,得到的数字实际上会略微偏小。这就是为什么格式化程序会将其舍入为 1.9%。

你可以通过根本不使用double数据类型来解决这个问题:

formattedValue = numberFormat.format(new BigDecimal(number));
英文:

The problem with 0.0195 is that there is no double precision number that is exactly mathematically equal to it. When you write 0.0195 in program source code or parse the string "0.0195" into double, the number you get is actually a little bit less. That's why the formatter rounds it to 1.9%.

You can get around this by not using the double data type at all:

formattedValue = numberFormat.format(new BigDecimal(number));

huangapple
  • 本文由 发表于 2020年8月26日 06:20:35
  • 转载请务必保留本文链接:https://go.coder-hub.com/63587891.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定