英文:
Fill an array with powers of 3
问题
public class Power {public static void main(String[] args) {int base = 3, exponent = 9;int[] result = new int[10];result[0] = 1; // Initialize the first element of the array with 1System.out.println(result[0]);int i = 1; // Start from the second element of the arraywhile (exponent != 0){result[i] = result[i - 1] * base; // Multiply the previous element by the base and store in the current element--exponent;System.out.println(result[i]);i++;}}}
英文:
public class Power {public static void main(String[] args) {int base = 3, exponent = 9;int[] result = new int[10];System.out.println(result);while (exponent != 0){result * base = result;--exponent;System.out.println(result);}}}
What I would like this code to do is be able to Multiply 1*3 to make 3, put it inside of the array, and multiply it again, and so on and so forth. Basically, it needs to output, 1 3 9 27 81 243 729 2187 6561 19683. How can I store it inside of the array, and also multiply it again?
答案1
得分: 0
你可以保留一个结果变量，并继续将其保存到一个数组中：
int index = 0;int[] result = new int[10];int current = 1;for (int i = 0; i < result.length; ++i) {result[i] = current;current *= 3;}System.out.println(Arrays.asString(result));
英文:
You could keep a result variable and continue saving it to an array:
int index = 0;int[] result = new int[10];int current = 1;for (int i = 0; i < result.length; ++i) {result[i] = current;current *= 3;}System.out.println(Arrays.asString(result));
答案2
得分: 0
你的第一个问题是赋值语句需要将变量名放在左边，表达式放在右边；将 result * base = result; 替换为 result = result * base;。
其次，result 是一个数组。你试图将它当作单个数字来处理。
第三，如果你想要填充一个数组，使用一个 for 循环，而不是你目前的方式：
final int base = 3;final int[] result = new int[10];result[0] = 1;for (int i = 1; i < result.length; i++) {result[i] = result[i - 1] * base;}
英文:
Your first problem is that assignments need the name on the left side, and the expression on the right side; replace result * base = result; by result = result * base;.
Secondly, result is an array. You’re trying to treat it as a single number.
Thirdly, if you want to fill an array, use a for loop instead of what you currently have:
final int base = 3;final int[] result = new int[10];result[0] = 1;for (int i = 1; i < result.length; i++) {result[i] = result[i - 1] * base;}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论