英文:
how do you round up a double user input value in java?
问题
我是一名正在制作简单评分系统的学生，我在如何做这个方面遇到了困难。
当我输入特定的数字时，它会跳过我的else-if语句，而进入else语句。
这些数字分别是98、67、98、80和81，我不知道为什么会这样。
以下是我的代码：
public static void main(String[] args) {double grade = 0, tgrade = 0, r;int gcount = 0;for (int i = 0; i < 5; i++) {grade = Integer.parseInt(JOptionPane.showInputDialog(null, "输入成绩："));tgrade = tgrade + grade;gcount++;System.out.println(gcount + ". " + "成绩：" + grade);}DecimalFormat c = new DecimalFormat("##.##");tgrade = tgrade / 500 * 100;r = new Double(c.format(tgrade)).doubleValue();System.out.print("总成绩：" + (tgrade) + "\n");if (r >= 95 && r <= 100) {JOptionPane.showMessageDialog(null, "高荣誉");} else if (r >= 90 && r <= 94) {JOptionPane.showMessageDialog(null, "荣誉");} else if (r >= 85 && r <= 89) {JOptionPane.showMessageDialog(null, "良好");} else if (r >= 80 && r <= 84) {JOptionPane.showMessageDialog(null, "合格");} else if (r >= 75 && r <= 79) {JOptionPane.showMessageDialog(null, "及格，但合格");} else {JOptionPane.showMessageDialog(null, "低分");}}
英文:
Im a student whos making a simple grading system and Im struggling on how to do this
when I type in a specific number it go down to else bypassing my else-if statements
the numbers are 98, 67, 98, 80 and 81 and i dont know why this happens
Here's my code:
public static void main(String[]args) {double grade=0,tgrade=0,r;int gcount=0;for (int i = 0; i<5;i++) {grade = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter the grades "));tgrade = tgrade+grade;gcount++;System.out.println(gcount+". "+"grade: "+grade );}DecimalFormat c = new DecimalFormat("##.##");tgrade = tgrade/500*100;r = new Double(c.format(tgrade)).doubleValue();System.out.print("Total Grade: "+(tgrade)+"\n");if (r >= 95 && r <=100) {JOptionPane.showMessageDialog(null, "High Honor");}else if (r >= 90 && r <= 94){JOptionPane.showMessageDialog(null, "Honor");}else if (r >=85 && r <= 89) {JOptionPane.showMessageDialog(null, "Good");}else if (r>=80 && r<=84) {JOptionPane.showMessageDialog(null, "Satisfactory");}else if (r>=75 && r<= 79) {JOptionPane.showMessageDialog(null, "Low pass, but certifying");}else {JOptionPane.showMessageDialog(null, "Low Failure");}}
}
答案1
得分: 1
变量 r 是双精度浮点数。
例如：
你有这些数字：98、67、98、80 和 81
平均值是：424/5 = 84.8
这个值 84.8 不符合你写的条件：
如果 (r >= 85 && r <= 89)
如果 (r >= 80 && r <= 84)
因此它不满足条件。
你可以使用以下选项。
第一选项：不要使用以下范围：
如果 (r >= 95) {
JOptionPane.showMessageDialog(null, "High Honor");
}else if (r >= 90){
JOptionPane.showMessageDialog(null, "Honor");
}else if (r >= 85){
JOptionPane.showMessageDialog(null, "Good");
}else if (r >= 80){
JOptionPane.showMessageDialog(null, "Satisfactory");
}else if (r >= 75){
JOptionPane.showMessageDialog(null, "Low pass, but certifying");
}else {
JOptionPane.showMessageDialog(null, "Low Failure");
}
第二选项：如果你在使用范围，请像以下方式构建条件：
如果 (r >= 95 && r < 100) {
JOptionPane.showMessageDialog(null, "High Honor");
}else if (r >= 90 && r < 95){
JOptionPane.showMessageDialog(null, "Honor");
}else if (r >= 85 && r < 90) {
JOptionPane.showMessageDialog(null, "Good");
}else if (r >= 80 && r < 85) {
JOptionPane.showMessageDialog(null, "Satisfactory");
}else if (r >= 75 && r < 80) {
JOptionPane.showMessageDialog(null, "Low pass, but certifying");
}else {
JOptionPane.showMessageDialog(null, "Low Failure");
}
第三选项：如果你需要四舍五入，可以使用 Math.abs 来从 double r 中提取绝对值。
示例：
Math.abs(r)
英文:
You variable r is double.
For example :
You have these numbers : 98, 67, 98, 80 and 81The average is : 424/5 = 84.8
This value 84.8 doesnot fit both the condition you wrote :
if (r >=85 && r <= 89)if (r>=80 && r<=84)
Hence it is going out.
You can use the below options.
FIRST Option : Don't use the range as below :
if (r >= 95) {JOptionPane.showMessageDialog(null, "High Honor");}else if (r >= 90){JOptionPane.showMessageDialog(null, "Honor");}else if (r >= 85){JOptionPane.showMessageDialog(null, "Good");}else if (r >= 80){JOptionPane.showMessageDialog(null, "Satisfactory");}else if (r >= 75){JOptionPane.showMessageDialog(null, "Low pass, but certifying");}else {JOptionPane.showMessageDialog(null, "Low Failure");}
SECOND Option : If you are using range then frame the conditions like below :
if (r >= 95 && r <= 100) {JOptionPane.showMessageDialog(null, "High Honor");}else if (r >= 90 && r < 95){JOptionPane.showMessageDialog(null, "Honor");}else if (r >= 85 && r < 90) {JOptionPane.showMessageDialog(null, "Good");}else if (r >= 80 && r < 85) {JOptionPane.showMessageDialog(null, "Satisfactory");}else if (r >= 75 && r < 80) {JOptionPane.showMessageDialog(null, "Low pass, but certifying");}else {JOptionPane.showMessageDialog(null, "Low Failure");}
THIRD Option : If you need to round up then you can use Math.abs to extract the absolute value from the double r
Example :
Math.abs(r)
答案2
得分: -1
将else if (r>=80 && r<=84)更改为else if (r>=80 && r<=84)，然后它就会起作用。
英文:
changeelse if (r>=80 && r<=84) to else if (r>=80 && r<=84) and it will work
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