Amplify身份验证事件在安卓设备上无法正常工作。

huangapple
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英文:

Amplify Auth events don't work in android

问题

我正在开发一个使用AWS Amplify库进行身份验证的应用程序。
我尝试通过查看Amplify的身份验证事件来检查登录状态，但是它不起作用。
我尝试通过logcat进行验证，但它只显示了获取输出。

  1. Amplify.Auth.fetchAuthSession(
  2.     result -> Log.i("AmplifyQuickstart", result.toString()),
  3.     error -> Log.e("AmplifyQuickstart", error.toString())
  4. );
  6. Amplify.Hub.subscribe(HubChannel.AUTH, hubEvent -> {
  7.     if (hubEvent.getName().equals(InitializationStatus.SUCCEEDED.toString())) {
  8.         Log.i("AuthQuickstart", "身份验证成功初始化");
  9.     } else if (hubEvent.getName().equals(InitializationStatus.FAILED.toString())) {
  10.         Log.i("AuthQuickstart", "身份验证未能成功初始化");
  11.     } else {
  12.         switch (AuthChannelEventName.valueOf(hubEvent.getName())) {
  13.             case SIGNED_IN:
  14.                 Log.i("AuthQuickstart", "刚刚完成登录。");
  15.                 break;
  16.             case SIGNED_OUT:
  17.                 Log.i("AuthQuickstart", "刚刚登出。");
  18.                 break;
  19.             case SESSION_EXPIRED:
  20.                 Log.i("AuthQuickstart", "身份验证会话刚刚过期。");
  21.                 break;
  22.             default:
  23.                 Log.w("AuthQuickstart", "未处理的身份验证事件：" + AuthChannelEventName.valueOf(hubEvent.getName()));
  24.                 break;
  25.         }
  26.     }
  27. });
英文:

I'm working in on an app that uses authentication from the AWS Amplify library.
I tried to check the sign-in state by looking at Amplify's auth events, but it
doesn't work. I tried to verify with logcat, but it only shows me the output of
the fetch.

  1. Amplify.Auth.fetchAuthSession(
  2.     result -> Log.i("AmplifyQuickstart", result.toString()),
  3.     error -> Log.e("AmplifyQuickstart", error.toString())
  4. );
  6. Amplify.Hub.subscribe(HubChannel.AUTH, hubEvent -> {
  7.     if (hubEvent.getName().equals(InitializationStatus.SUCCEEDED.toString())) {
  8.         Log.i("AuthQuickstart", "Auth successfully initialized");
  9.     } else if (hubEvent.getName().equals(InitializationStatus.FAILED.toString())) {
  10.         Log.i("AuthQuickstart", "Auth failed to succeed");
  11.     } else {
  12.         switch (AuthChannelEventName.valueOf(hubEvent.getName())) {
  13.             case SIGNED_IN:
  14.                 Log.i("AuthQuickstart", "Auth just became signed in.");
  15.                 break;
  16.             case SIGNED_OUT:
  17.                 Log.i("AuthQuickstart", "Auth just became signed out.");
  18.                 break;
  19.             case SESSION_EXPIRED:
  20.                 Log.i("AuthQuickstart", "Auth session just expired.");
  21.                 break;
  22.             default:
  23.                 Log.w("AuthQuickstart", "Unhandled Auth Event: " + AuthChannelEventName.valueOf(hubEvent.getName()));
  24.                 break;
  25.         }
  26.     }
  27. });

答案1

得分: 0

以下是翻译好的部分：

一种我成功解决该问题的方法是将错误 lambda 引用传递给 errorAuthenticationHandle 函数，如下所示：

  1. Amplify.Auth.signIn(this.userName, password,
  2.     result -> Log.i("AuthQuickstart", result.isSignInComplete() ?
  3.         "登录成功" : "登录未完成"),
  4.     this::errorAuthenticationHandle
  5. );
  7. private void errorAuthenticationHandle(AuthException error) {
  8.     Log.e("AmplifyQuickstart", error.toString());
  10.     switch (getErrorNumber(error)) {
  11.         // 服务器要求重置密码
  12.         case RESET:
  13.             // 一些代码
  14.             break;
  16.         case FAILED:
  17.             // 一些代码
  18.             break;
  19.     }
  20. }
英文:

One way that I succeed to handle the problem is to pass the error lambda
reference to errorAuthenticationHandle function as follows:

  1. Amplify.Auth.signIn(this.userName, password,
  2.     result -> Log.i("AuthQuickstart", result.isSignInComplete() ?
  3.         "Sign in succeeded" : "Sign in not complete"),
  4.     this::errorAuthenticationHandle
  5. );
  7. private void errorAuthenticationHandle(AuthException error) {
  8.     Log.e("AmplifyQuickstart", error.toString());
  10.     switch (getErrorNumber(error)) {
  11.         // Server require password reset
  12.         case RESET:
  13.             // Some code
  14.             break;
  16.         case FAILED:
  17.             // Some code
  18.             break;
  19.     }
  20. }

huangapple
  • 本文由 发表于 2020年8月25日 11:53:36
  • 转载请务必保留本文链接：https://go.coder-hub.com/63571815.html
  • amazon-cognito
  • android
  • aws-amplify
  • java
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