英文:
Java Reactive. How to wait for all data in flux and then process them
问题
Flux<Views> views = someRepository.findAllByUsersIn(userId).doOnNext(v -> {
v.setInterlocutor(v.getUsers().stream().filter(u -> !userId.equals(u)).findFirst().orElse(null));
});
return Flux.zip(views.map(view -> conversionService.convert(view, ResponseViewDto.class)), getUserInfo(views).flux())
.flatMap(fZip -> {
ResponseViewDto dto = fZip.getT1();
dto.setInterlocutor(fZip.getT2().get(dto.getInter()));
return Flux.just(dto);
});
英文:
I'm getting data from mongo reactive repository and updating it. Then I have to collect all data in one collection and path it to another service to get more info. Then I should map them in one Flux. My code is:
Flux<Views> views = someRepository.findAllByUsersIn(userId).doOnNext(v -> {
v.setInterlocutor(v.getUsers().stream().filter(u -> !userId.equals(u)).findFirst().orElse(null));
});
return Flux.zip(views.map(view -> conversionService.convert(view, ResponseViewDto.class)), getUserInfo(views).flux())
.flatMap(fZip -> {
ResponseViewDto dto = fZip.getT1();
dto.setInterlocutor(fZip.getT2().get(dto.getInter()));
return Flux.just(dto);
});
getUserInfo does collecting usersId and sends them to another service and returns expanded info.
I found that getting from DB calls 2 times and I can understand why, but is there any solution to do it once and still be not blocking.
答案1
得分: 0
感谢Adhika Setya Pramudita的帮助。我所需的方法就是使用cache()方法。
英文:
Thanks to Adhika Setya Pramudita for help. The way to do what I need is just to use cache() method
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