英文:
getting Out of Range Compile Time Error in the Date Constructor
问题
我从 API 调用中得到一个日期值 1598331600000我正在尝试使用 SimpleDateFormat 将其转换为可读格式但是在日期构造函数中我得到了超出范围的编译时错误这是我的程序public class Test {public static void main(String[] args) {// TODO Auto-generated method stubCalendar cal = Calendar.getInstance();Date date = new java.sql.Date(1598331600000);SimpleDateFormat sdf = new java.text.SimpleDateFormat("MMddyyyy");String formattedDate = sdf.format(date);System.out.println(formattedDate);}}请告诉我如何解决这个错误。
英文:
I am getting a date value as 1598331600000 from a API call
I am trying to convert this to Readable format using SimpleDateFormat
But i am getting Out of Range Compile Time Error in the Date Constructor
This is my Program
public class Test {public static void main(String[] args) {// TODO Auto-generated method stubCalendar cal = Calendar.getInstance();Date date = new java.sql.Date(1598331600000);SimpleDateFormat sdf = new java.text.SimpleDateFormat("MMddyyyy");String formattedDate = sdf.format(date);System.out.println(formattedDate);}}
Could you please let me know how to resolve this error .
答案1
得分: 3
1598331600000没有后缀时被视为int，而此值对于int来说过大了（int可以容纳最大约为20亿的值，即2的31次方减1）。请使用L后缀来表示long类型，long类型可以容纳最大值为2的63次方减1：1598331600000L。
英文:
1598331600000 without a suffix is treated as an int, and this value is too big for it (int can hold values up to around 2 billion, 2^31 - 1). Use L suffix for long type, which can hold values up to 2^63 - 1: 1598331600000L.
答案2
得分: 2
我建议使用 java-8 日期时间 API，停止使用旧的 Calendar、SimpleDateFormat。
Instant.ofEpochMilli(1598331600000l).atZone(ZoneId.systemDefault()).format(DateTimeFormatter.ofPattern("MMddyyyy")) //08252020
英文:
I would recommend to use java-8 date time api, and stop using legacy Calendar, SimpleDateFormat
Instant.ofEpochMilli(1598331600000l).atZone(ZoneId.systemDefault()).format(DateTimeFormatter.ofPattern("MMddyyyy")) //08252020
答案3
得分: 0
您的价值在此被视为整数。
Date date = new java.sql.Date(1598331600000L);
构造函数可以接受长整型数值。像这样：
long millis = System.currentTimeMillis();Date date = new java.sql.Date(millis);
因此它会抛出错误。
尝试运行这段代码：
import java.util.*;import java.text.SimpleDateFormat;public class Main {public static void main(String[] args) {Calendar cal = Calendar.getInstance();/*long millis = System.currentTimeMillis(); //<---- 这也可以工作Date date = new java.sql.Date(millis);*/Date date = new java.sql.Date(1598331600000L); //<--- 在这里查看L表示长整型SimpleDateFormat sdf = new java.text.SimpleDateFormat("MMddyyyy");String formattedDate = sdf.format(date);System.out.println(formattedDate);}}
输出：
08252020
英文:
Your value here is treated as integer.
Date date = new java.sql.Date(1598331600000);
The constructor can take Long values. Like this :
long millis=System.currentTimeMillis();Date date = new java.sql.Date(millis);
Hence it is throwing the error.
Try out this code :
import java.util.*;import java.text.SimpleDateFormat;public class Main{public static void main(String[] args) {Calendar cal = Calendar.getInstance();/*long millis=System.currentTimeMillis(); <---- This also worksDate date = new java.sql.Date(millis);*/Date date = new java.sql.Date(1598331600000L); // <---Look the L for Long hereSimpleDateFormat sdf = new java.text.SimpleDateFormat("MMddyyyy");String formattedDate = sdf.format(date);System.out.println(formattedDate);}}
Output :
08252020
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