英文:
iterating over two java streams with the same size and override values from one on another
问题
我有两个列表，它们的大小相同。我想同时迭代这两个列表，并将一个列表中的值覆盖到另一个列表中。
例如，我有两个列表 ListA 和 ListB，其中包含一些数据，它们可以通过 id 进行比较，我想要得到如下结果：
List<SomeObject> listA;
List<AnotherObject> listB;
listA: [
[id=111;
name='AAA';
age=65],
[id=222;
name='BBB';
age=11]
]
listB: [
[id=111;
name='';
age=null],
[id=222;
name='';
age=null]
]
result: [
[id=111;
name='AAA';
age=65],
[id=222;
name='BBB';
age=11]
]
它们当然还有一些其他不同的属性，应该保持原样。所以我只需要覆盖其中的两个属性。
英文:
I have two Lists and they have same size. I would like to iterate over both of them simultaneously and override values from one stream on another stream.
For example I have two lists ListA and ListB with some data and they can be compared by id and I would like to get as a result like below:
List<SomeObject> listA;
List<AnotherObject> listB;
listA: {
[id=111;
name='AAA';
age=65],
[id=222;
name='BBB';
age=11],
}
listB: {
[id=111;
name='';
age=null],
[id=222;
name='';
age=null],
}
result:{
[id=111;
name='AAA';
age=65],
[id=222;
name='BBB';
age=11],
}
They have some other properties of course which are different and should stay as it is. So I need to override just two of them
答案1
得分: 1
Sure, here's the translation:
- 从一个列表（按
id分组）创建一个映射，例如从 'listB'。 - 使用流或循环遍历另一个列表（
listA），对于每个项目，从创建的映射中找到相应的按id匹配的项目。 - 如果条目按
id匹配，则替换所有值为null或空字符串的内容。
英文:
- Create a map from one list (grouping by
id) for example from 'listB' - Iterate by other list (
listA) with stream or for-loop, and for every item find byidcorresponding item from created map. - If entries match by
idreplace all values that arenullor empty string.
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