英文:
Is it possible to pass an object parameter as an id in the find view by id
问题
这是我自然而然地完成这个任务的方式，还有其他可能的可行方法吗？
public void error_checker(String Text_ID, int id, int id_2, String greater_num) {
if (id > id_2) {
TextView TextView = findViewById(R.id.Text_ID);
TextView.setText("你的答案不能大于" + (greater_num));
} else {
}
}
英文:
Here is how I would naturally do this, are there any other possible ways that work?
public void error_checker(String Text_ID, int id,int id_2,String greater_num){
if (id>id_2){
TextView TextView = findViewById(R.id.Text_ID);
TextView.setText(Integer.parseInt("You Answer Can't be Greater Than"+(greater_num));
} else {
}
}
答案1
得分: 0
你可以像这样做：
TextView textView = findViewById(getResources().getIdentifier(Text_ID, "id", getPackageName()));
其中，Text_ID 是你的视图的ID（不带R.id.前缀）。
英文:
You can do it like this:
TextView textView = findViewById(getResources().getIdentifier(Text_ID, "id", getPackageName()););
Where Text_ID is the ID of your view (without the R.id. prefix)
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