Explain why the Wrong Output Happened?

public class ArrayIntro
{
	public static void main(String[] args)
	{
		int[] a;
		a=new int[10];
		Scanner sc =new Scanner(System.in);
		for(int i=0;i<10;i++)
		{
			a[i]=sc.nextInt();	
		}
		for(int e:a)
		{
			System.out.print(e+' ');
		}
	}
}

Input:1 2 3 4 5 6 7 8 9 10<br>
Output:33343536373839404142

Its mean it added 32 to each number

Just try with below code.

As you are printing sout inside for loop, it's printing sum of number and Space( ' '). And space have ASCII value of 32, so you are able to see every element with added value of 32.

For ASCII Or Unicode you can refer this link, it will help you.

Simply you put something like this System.out.print(new Integer(' '));, it will print 32.

If you want to add space only then go with double quote.
System.out.print(e+" ");.

Single quote consider as character and charater added with Integer will summing up with their ASCII code.

public static void main(String[] args)
    {
        int[] a;
        a=new int[10];
        Scanner sc =new Scanner(System.in);
        for(int i=0;i<10;i++)
        {
            a[i]=sc.nextInt();  
        }
        for(int e:a)
        {
            System.out.print(e+" ");
        }
    }

To put it simply, ' ' is a character in ASCII and the value of it is 32. So, as far as I know, you might want it the just print directly so you can just replace ' ' with " ". Always remember that single quotes are for characters and double quotes are for strings.

For your answer you can just do this:System.out.print(e+" ");

Instead of this: System.out.print(e+' ');

In short, to fix your program, you need to use " " (with double quotes) instead of ' '.

The issue is that the + operator has two different meanings in Java.

• If either of the operands is a String, then + means "concatenate these two operands together". If the other operand is not a String, then it will have to be converted somehow, and there are some rules around how to do this.
• If neither operand is a String, then + means "add these two operands together" - that is, they are treated as numbers. They can be added as double values, float values, long values or int values, depending on the data types. But if they are short, byte or char, they will be treated as int. This is called binary numeric promotion, and is explained in detail in the Java Language Specification.

Now in Java, single quotes are used to delimit a char literal. So when you write e + ' ', you're adding an int to a char. This is addition - the char is treated as an int, and the operands are added as numbers. The number corresponding to is 32, since that's the numeric value in the character encoding that Java uses, which is something like UTF-16. Contrary to some other answers on this page, it's not ASCII.

Double quotes are used to delimit a String literal. So if you write e + " ", the operands are an int and a String. That means you're not adding any more, but concatenating. The int is converted to a String first, then concatenated to " ", which will give you the result you're expecting.