Trying to implement Dijsktra in Java using priority queue and using hash map for decrease key

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英文:

Trying to implement Dijsktra in Java using priority queue and using hash map for decrease key

问题

// this has a bug which I dont know how to find
public int networkDelayTime(int[][] times, int N, int K) {
    Map<Integer, Map<Integer,Integer>> adjListWithDistance = new HashMap<>();
    // using this distance Map from K as comparator in priority queue
    Map<Integer, Integer> dMapFromK = new HashMap<>();

    PriorityQueue<Integer> pq = new PriorityQueue<>((k1,k2) -> dMapFromK.get(k1) - dMapFromK.get(k2));
    HashSet<Integer> v = new HashSet<>();

    for(int i = 0; i < times.length; i++){
        int source = times[i][0];
        int dest = times[i][1];
        int dist = times[i][2];

        adjListWithDistance.putIfAbsent(source, new HashMap<>());
        adjListWithDistance.get(source).put(dest, dist);
    }

    dMapFromK.put(K, 0);
    pq.add(K);

    int res = 0;
    while(!pq.isEmpty()){
        int fromNode = pq.poll();
        if(v.contains(fromNode)) continue;
        v.add(fromNode);
        int curDist = dMapFromK.get(fromNode);
        res = curDist;

        if(!adjListWithDistance.containsKey(fromNode)) {
            continue;
        }
        for(Integer toNode: adjListWithDistance.get(fromNode).keySet()){
            if(v.contains(toNode)) continue;
            int toNodeDist = adjListWithDistance.get(fromNode).get(toNode);
            if(dMapFromK.containsKey(toNode) && dMapFromK.get(toNode) <= curDist + toNodeDist){
                continue;
            } else {
                if(!dMapFromK.containsKey(toNode)){
                    dMapFromK.put(toNode, curDist + toNodeDist);
                    pq.offer(toNode);
                } else{
                    dMapFromK.put(toNode, curDist + toNodeDist);
                }
            }
        }
    }

    if(dMapFromK.keySet().size() != N)
        return -1;
    return Collections.max(dMapFromK.values());
}
英文:

Full Disclosure - I am doing this exercise to solve this problem on Leetcode - https://leetcode.com/problems/network-delay-time/

I find that this code is not working for certain test cases. I have been trying to debug this for a few hours havent had any luck. Can anyone help the bug in this code.


// this has a bug which I dont know how to find
public int networkDelayTime(int[][] times, int N, int K) {
Map&lt;Integer, Map&lt;Integer,Integer&gt;&gt; adjListWithDistance = new HashMap&lt;&gt;();
// using this distance Map from K as comparator in priority queue
Map&lt;Integer, Integer&gt; dMapFromK = new HashMap&lt;&gt;();
PriorityQueue&lt;Integer&gt; pq = new PriorityQueue&lt;&gt;((k1,k2) -&gt; dMapFromK.get(k1) - dMapFromK.get(k2));
HashSet&lt;Integer&gt; v = new HashSet&lt;&gt;();
for(int i = 0; i &lt; times.length; i++){
int source = times[i][0];
int dest = times[i][1];
int dist = times[i][2];
adjListWithDistance.putIfAbsent(source, new HashMap&lt;&gt;());
adjListWithDistance.get(source).put(dest, dist);
//if(source == K){
//    dMapFromK.put(dest, dist);
//    pq.add(dest);
// }
}
// distance from K to K is 0
dMapFromK.put(K, 0);
pq.add(K);
// we have already added all nodes from K to PQ, so we dont need to process K again
//v.add(K);
//System.out.println(adjListWithDistance);
//System.out.println(dMapFromK);
int res = 0;
while(!pq.isEmpty()){
int fromNode = pq.poll();
if(v.contains(fromNode)) continue;
v.add(fromNode);
int curDist = dMapFromK.get(fromNode);
res = curDist;
//System.out.println(&quot;current node - &quot; + fromNode);
if(!adjListWithDistance.containsKey(fromNode)) {
continue;
}
for(Integer toNode: adjListWithDistance.get(fromNode).keySet()){
// BIG BUGGGGG, adding the below line is also causing a bug , not sure why
if(v.contains(toNode)) continue;
int toNodeDist = adjListWithDistance.get(fromNode).get(toNode);
if(dMapFromK.containsKey(toNode) &amp;&amp; dMapFromK.get(toNode) &lt;= curDist + toNodeDist){
continue;
}else {
if(!dMapFromK.containsKey(toNode)){
dMapFromK.put(toNode, curDist + toNodeDist);
// need to add map entry first before adding to priority queue else it throws an exception
pq.offer(toNode);
}else{
dMapFromK.put(toNode, curDist + toNodeDist);
}
}
}
}
System.out.println(adjListWithDistance);
System.out.println(dMapFromK);
if(dMapFromK.keySet().size() != N)
return -1;
//return res;
return Collections.max(dMapFromK.values());
}

TLDR: This implementation of Dijsktra is not correct and doesn't return the shortest path for certain nodes for certain test cases. I'm not sure why, and I need help debugging what mistake I am making.

答案1

得分: 1

以下是翻译后的内容:

这几乎是相同的,将会通过:

public final class Solution {
    public static final int networkDelayTime(
        final int[][] times,
        int n,
        final int k
    ) {
        Map<Integer, Map<Integer, Integer>> graph = new HashMap<>();

        for (final int[] node : times) {
            graph.putIfAbsent(node[0], new HashMap<>());
            graph.get(node[0]).put(node[1], node[2]);
        }

        Queue<int[]> queue = new PriorityQueue<>((a, b) -> (a[0] - b[0]));
        queue.add(new int[] {0, k});
        boolean[] visited = new boolean[n + 1];
        int total = 0;

        while (!queue.isEmpty()) {
            int[] curr = queue.remove();
            int currNode = curr[1];
            int currTime = curr[0];

            if (visited[currNode]) {
                continue;
            }

            visited[currNode] = true;
            total = currTime;
            n--;

            if (graph.containsKey(currNode)) {
                for (final int next : graph.get(currNode).keySet()) {
                    queue.add(new int[] {currTime + graph.get(currNode).get(next), next});
                }
            }
        }

        return n == 0 ? total : -1;
    }
}

以下是使用堆的 Python 版本,如果你有兴趣的话:

from typing import List
import heapq
from collections import defaultdict

class Solution:
    def networkDelayTime(self, times: List[List[int]], n, k) -> int:
        queue = [(0, k)]
        graph = collections.defaultdict(list)
        memo = {}

        for u_node, v_node, time in times:
            graph[u_node].append((v_node, time))

        while queue:
            time, node = heapq.heappop(queue)
            if node not in memo:
                memo[node] = time
                for v_node, v_time in graph[node]:
                    heapq.heappush(queue, (time + v_time, v_node))
        return max(memo.values()) if len(memo) == n else -1

在 C++ 中,我们将使用快速整数类型:

// 以下部分可能会微不足道地提高执行时间;
// 可以删除;
static const auto __optimize__ = []() {
    std::ios::sync_with_stdio(false);
    std::cin.tie(NULL);
    std::cout.tie(NULL);
    return 0;
}();

// 大多数头文件已经包含;
// 可以删除;
#include <cstdint>
#include <vector>
#include <algorithm>

#define MAX INT_MAX
using ValueType = std::uint_fast16_t;

static const struct Solution {
    static const int networkDelayTime(
        const std::vector<vector<int>>& times, 
        int n, 
        const int k
    ) {
        std::vector<ValueType> distances(n + 1, MAX);
        distances[k] = 0;

        for (ValueType index = 0; index < n; index++) {
            for (const auto& time : times) {
                const ValueType u_node = time[0];
                const ValueType v_node = time[1];
                const ValueType uv_weight = time[2];

                if (distances[u_node] != MAX && distances[v_node] > distances[u_node] + uv_weight) {
                    distances[v_node] = distances[u_node] + uv_weight;
                }
            }
        }

        ValueType total_time = 0;

        for (auto index = 1; index <= n; index++) {
            total_time = std::max(total_time, distances[index]);
        }

        return total_time == MAX ? -1 : total_time;
    }
};
英文:

This is almost the same, will pass through:

public final class Solution {
public static final int networkDelayTime(
final int[][] times,
int n,
final int k
) {
Map&lt;Integer, Map&lt;Integer, Integer&gt;&gt; graph = new HashMap&lt;&gt;();
for (final int[] node : times) {
graph.putIfAbsent(node[0], new HashMap&lt;&gt;());
graph.get(node[0]).put(node[1], node[2]);
}
Queue&lt;int[]&gt; queue = new PriorityQueue&lt;&gt;((a, b) -&gt; (a[0] - b[0]));
queue.add(new int[] {0, k});
boolean[] visited = new boolean[n + 1];
int total = 0;
while (!queue.isEmpty()) {
int[] curr = queue.remove();
int currNode = curr[1];
int currTime = curr[0];
if (visited[currNode]) {
continue;
}
visited[currNode] = true;
total = currTime;
n--;
if (graph.containsKey(currNode)) {
for (final int next : graph.get(currNode).keySet()) {
queue.add(new int[] {currTime + graph.get(currNode).get(next), next});
}
}
}
return n == 0 ? total : -1;
}
}

Here is a Python version using heap, if you'd be interested:

from typing import List
import heapq
from collections import defaultdict
class Solution:
def networkDelayTime(self, times: List[List[int]], n, k) -&gt; int:
queue = [(0, k)]
graph = collections.defaultdict(list)
memo = {}
for u_node, v_node, time in times:
graph[u_node].append((v_node, time))
while queue:
time, node = heapq.heappop(queue)
if node not in memo:
memo[node] = time
for v_node, v_time in graph[node]:
heapq.heappush(queue, (time + v_time, v_node))
return max(memo.values()) if len(memo) == n else -1

In C++, we'd just use a fast integer type:

// The following block might trivially improve the exec time;
// Can be removed;
static const auto __optimize__ = []() {
std::ios::sync_with_stdio(false);
std::cin.tie(NULL);
std::cout.tie(NULL);
return 0;
}();
// Most of headers are already included;
// Can be removed;
#include &lt;cstdint&gt;
#include &lt;vector&gt;
#include &lt;algorithm&gt;
#define MAX INT_MAX
using ValueType = std::uint_fast16_t;
static const struct Solution {
static const int networkDelayTime(
const std::vector&lt;vector&lt;int&gt;&gt;&amp; times, 
int n, 
const int k
) {
std::vector&lt;ValueType&gt; distances(n + 1, MAX);
distances[k] = 0;
for (ValueType index = 0; index &lt; n; index++) {
for (const auto&amp; time : times) {
const ValueType u_node = time[0];
const ValueType v_node = time[1];
const ValueType uv_weight = time[2];
if (distances[u_node] != MAX &amp;&amp; distances[v_node] &gt; distances[u_node] + uv_weight) {
distances[v_node] = distances[u_node] + uv_weight;
}
}
}
ValueType total_time = 0;
for (auto index = 1; index &lt;= n; index++) {
total_time = std::max(total_time, distances[index]);
}
return total_time == MAX ? -1 : total_time;
}
};

References

  • For additional details, please see the Discussion Board where you can find plenty of well-explained accepted solutions with a variety of languages including low-complexity algorithms and asymptotic runtime/memory analysis<sup>1, 2</sup>.

huangapple
  • 本文由 发表于 2020年8月15日 07:22:41
  • 转载请务必保留本文链接:https://go.coder-hub.com/63421093.html
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