Is there any way to get Boolean's string binding rather than its boolean binding in Java

Here's what I need to do:

    public void verifyConditionSatisfies( Boolean condition){
  
    			if (condition) {
    				System.out.println(condition.toString()+ "satisfies)//This is the part i need to get its String binding, not boolean evaluated version
                }else{
                    System.out.println(condition.toString()+ " does not satisfy)
                }

	}

Here's an intended usage:

verifyConditionSatisfies(10>9)

should evaluate as

"10>9 satisfies"

As mentioned in comments, getting a boolean expression 10>9 as a String is not possible. Giving the expression as a String "10>9" might be easier to do it.

Here is an unorthodox way to do it:

public class BooleanEval {
	public static void main(String[] args) throws ScriptException {
		System.out.println(new BooleanEvaluation("10>9"));
        System.out.println(new BooleanEvaluation("25<3"));
	}

	public static class BooleanEvaluation {
		private static final ScriptEngine javaScriptEngine = new ScriptEngineManager().getEngineByName("JavaScript");
		private String expression;
		private boolean evaluation;

		public BooleanEvaluation(String eval) throws ScriptException {
			this.expression = eval;
			this.evaluation = Boolean.parseBoolean(String.valueOf(javaScriptEngine.eval(expression)));
		}

		@Override
		public String toString() {
			String evalString = evaluation ? "satisfies" : "does not satisfy";
			return expression + " " + evalString;
		}
	}
}

Outputs:

10>9 satisfies
25<3 does not satisfy

This

  verifyConditionSatisfies(10>9);

is effectively evaluated as

  Boolean temp = 10 > 9;
  verifyConditionSatisfies(temp);

The method is unaware of how its argument was calculated.
The character sequence 1, 0, >, 9 exists only in source code.

So, the answer is "no".