英文:
Auto Conversion of floating point number to int. - Java
问题
当我在编写程序时忘记写Math.round()，当我回顾代码时，我看到了这个代码：
int number = 1/2;
为什么这不会引发一个错误，显示为required type: int | provided: double？
注意：如果这是一个愚蠢的问题，请原谅，我是编程新手。
英文:
I was writing a program and forgot to write Math.round() and when I was reviewing the code I saw this
int number = 1/2;
why doesn't this raise an error of
required type: int | provided:double?
Note: If this is a silly question please forgive I new to programming.
答案1
得分: 1
这是一种自动类型转换。在这里，变量'number'存储了自动转换为整数0的值。
然而，自动类型转换并不总是有效。当你写int number = 0.5;时会出现错误，但是当你写int number = (int) 0.5;时，这被称为显式类型转换，此时number存储0的值。
英文:
its an automatic type conversion.
Here the variable 'number' stores the auto converted value to int 0.
well auto type casting doesn't always work.
when you write int number = 0.5; it will give an error
but when you write int number = (int) 0.5; its called an explicit type casting and now number stores 0 value.
答案2
得分: 1
Sure, here's the translated content:
通常使用 double 进行数学运算的话，很可能会得到 double 的结果；而对于整数，则会得到一个 int 的结果。
然而，如果情况不是这样的话，Java 会截断小数点后面的数字，并将值设置为剩下的部分。例如：
3/4 = 1.5 => Java => 1
英文:
Normally doing math operations using double will most likely be giving double on the other hand for int it will give a int.
However, if thats not the case Java will strip the number after the dot (.) and set the value to whatever is left. Example:
3/4 = 1.5 => Java => 1
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