如何从Volley JSON响应中移除用户？

huangapple
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英文:

How do I Remove a User from a Volley JSON Response?

问题

Sure, here's the translated code part:

  1. 我想要通过其唯一标识（uniqid）删除特定用户，我已经从Volley响应中解析了JSON数据，以下是我的响应：
  3. 这是我的响应数据：
  5. [
  6.      {
  7.         "uniqid":"h5faweWtd", 
  8.         "name":"Test_1", 
  9.         "address":"tst", 
  10.         "email":"ru_tst@tst.cc", 
  11.         "mobile":"12345",
  12.         "city":"indd"
  13.     },{
  14.         "uniqid":"h5Wtd", 
  15.         "name":"Test_2", 
  16.         "address":"tst", 
  17.         "email":"ru_tst@tst.cc", 
  18.         "mobile":"1235945",
  19.         "city":"indd4"
  20.     },{
  21.         "uniqid":"h5Wtd25", 
  22.         "name":"Test_3", 
  23.         "address":"tdsdsst", 
  24.         "email":"rsfu_tst@tsfst.cc", 
  25.         "mobile":"1263345",
  26.         "city":"indd9"
  27.       }
  28.     ]
  30. 我想要通过其唯一标识（uniqid）删除特定用户。
  32. 在PHP中，我可以轻松地使用以下代码来实现：
  34. foreach ($UserList as $key => $value) {
  35.    if (in_array('uniqid', $uniqid_To_Remove)) {
  36.     unset($UserList[$key]);
  37.    }
  38. }
  39. $UserList = json_encode($UserList);
  41. echo $UserList;
  43. 但我想要在Android Java中获取响应并将其保存到共享首选项（SharedPreferences）中，当有互联网连接时，以及当没有互联网连接时，我想要从共享首选项中获取响应数据并根据其唯一标识（uniqid）删除特定用户。如何在Android Java中实现这个功能？
  45. 我正在尝试删除整个用户，问题是对象的位置不是固定的，它可以在数组中的任何位置。唯一固定的是我有的是uniqid。
英文:

i want to remove specific user with its uniquid i have parse json_encode($data); from volley response:

this is my response:

  1. [
  2. {
  3. "uniqid":"h5faweWtd", 
  4. "name":"Test_1", 
  5. "address":"tst", 
  6. "email":"ru_tst@tst.cc", 
  7. "mobile":"12345",
  8. "city":"indd"
  9. },{
  10. "uniqid":"h5Wtd", 
  11. "name":"Test_2", 
  12. "address":"tst", 
  13. "email":"ru_tst@tst.cc", 
  14. "mobile":"1235945",
  15. "city":"indd4"
  16. },{
  17. "uniqid":"h5Wtd25", 
  18. "name":"Test_3", 
  19. "address":"tdsdsst", 
  20. "email":"rsfu_tst@tsfst.cc", 
  21. "mobile":"1263345",
  22. "city":"indd9"
  23. }
  24. ]

I want to remove specific user with its uniquid

I'll easily do it in php with the help of this code:

  1. foreach ($UserList as $key => $value) {
  2. if (in_array('uniqid', $uniqid_To_Remove)) {
  3. unset($UserList[$key]);
  4. }
  5. }
  6. $UserList = json_encode($UserList);
  7. echo $UserList;

but i want to get response and save it to shared preferences when internet is available and when internet is not available: then i want to get response data from shared preferences and remove specific user from its uniqid. how to do it in android java?

I am trying to delete an entire user. the problem is that the object position is not static, it can be anywhere in the array. the only thing that is static that i have is uniqid.

答案1

得分: 0

以下是翻译好的内容：

要对一个 JsonArray 进行过滤，你可以尝试这样做：

  1. try {
  2.     List<JSONObject> filtered = new ArrayList<>();
  3.     JSONArray array = new JSONArray(); // 用实际的响应数组替换这里的 array
  5.     for (int i = 0; i < array.length(); i++) {
  6.         JSONObject obj = array.getJSONObject(i);
  7.         String id = obj.getString("uniqid");
  8.         if (!id.equals("h5Wtd25")) { // 根据你的过滤规则进行替换
  9.             filtered.add(obj); 
  10.         }
  11.     }
  12. } catch (JSONException e) {
  14. }
英文:

To filter a JsonArray, you could try this:

  1.        try {
  2. List&lt;JSONObject&gt; filtered = new ArrayList&lt;&gt;();
  3. JSONArray array = new JSONArray(); //Replace array with Response array
  4. for (int i = 0; i &lt; array.length(); i++) {
  5. JSONObject obj = array.getJSONObject(i);
  6. String id = obj.getString(&quot;uniqid&quot;);
  7. if (!id.equals(&quot;h5Wtd25&quot;)) { //Replace with your own filtered rule
  8. filtered.add(obj); 
  9. }
  10. }
  11. } catch (JSONException e) {
  12. }

答案2

得分: 0

private List<User> filterUserBasedOnId(List<User> users, String id){
return users.stream()
.filter(user -> !user.getUniqid().equals(id))
.collect(Collectors.toList());
}

Edit: You can have User class like this

public class User {
private String uniqid;
private String name;
private String address;
private String email;
private String mobile;
private String city;
// getter, setter
}

To get the List&lt;User&gt;, you need to parse it from json. You can refer to this

英文:

Assumed that you have the list of User, you can use filter to get your new list which remove the user with specific id

  1. private List&lt;User&gt; filterUserBasedOnId(List&lt;User&gt; users, String id){
  2. return users.stream()
  3. .filter( user -&gt; !user.getUniqid().equals(id))
  4. .collect(Collectors.toList());
  5. }

Edit: You can have User class like this

  1. public class User {
  2. private String uniqid;
  3. private String name;
  4. private String address;
  5. private String email;
  6. private String mobile;
  7. private String city;
  8. // getter, setter
  9. }

To get the List&lt;User&gt;, you need to parse it from json. You can refer to this

huangapple
  • 本文由 发表于 2020年8月12日 11:14:20
  • 转载请务必保留本文链接：https://go.coder-hub.com/63369222.html
  • android
  • java
  • json
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