英文:
Cron expression to run from 8PM to 6 AM
问题
我正在尝试为Spring的@Scheduled注解编写一个cron表达式，该表达式应在晚上8点到早上6点之间每隔10分钟执行一次 -
@Scheduled(cron = "0 */10 20-06 * * MON-FRI", zone = "America/New_York")
然而，上述的cron表达式会引发'Invalid inverted range'异常。当我尝试使用以下表达式时，
@Scheduled(cron = "0 */10 20-23,0-6 * * MON-FRI", zone = "America/New_York")
它在23点到0点之间不会运行。有没有办法编写一个cron表达式，可以涵盖23点到0点的时间段呢？
英文:
I am trying to write a cron expression for spring @Scheduled annotation that should be executed on the interval of 10 minutes between 8 PM to 6 AM -
@Scheduled(cron = "0 */10 20-06 * * MON-FRI", zone = "America/New_York")
However above cron is giving 'Invalid inverted range' exception. When I try
@Scheduled(cron = "0 */10 20-23,0-6 * * MON-FRI", zone = "America/New_York")
then it does not run between 23 and 0.
Is there any way to write a cron expression that can cover 23 to 0 hours also.
答案1
得分: 0
以下是翻译好的部分：
"> 每小时的第10分钟过后，从20点开始，以及每小时从0点到6点，从星期一到星期五的每一天。"
英文:
use below it should run from 8 PM to 6 AM
*/10 20,0-6 * * MON-FRI (min hour day month week)
above expression translates to -
> At every 10th minute past hour 20 and every hour from 0 through 6 on
> every day-of-week from Monday through Friday
答案2
得分: -1
我会期望你的第二个示例能够工作。不确定这是否是Spring实现中的错误。似乎是这样的。
这非常冗长，但你总是可以枚举整个值列表。
... 20,21,22,23,0,1,2,3,4,5,6 ...
英文:
I would expect your 2nd example to work. Not sure whether that's a bug in Spring's implementation. Seems like it.
It's very long-winded, but you could always just enumerate the entire list of values.
... 20,21,22,23,0,1,2,3,4,5,6 ...
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