How to add multiple arguments into XPath and replace %s to param

I have a string (e.g):

xpath = //tagname[text()='param1']/tagname[text()='param2']/tagname[text()='param3']

var param can increase from 1 => n (param1, param2, param3 .... paramN)

I want to build a function to add multiple arguments into xpath and I have to use String format in Java to put multiple value into xpath and do not know how to replace param to %s and use String format put multiple arguments.

> How can i build a function with replace param to %s?

Thank you so much.

You can different variables to be replaced within the [tag:xpath] as follows:

• Code Block:

  String str1 = "stringA";
  String str2 = "stringB";
  String str3 = "stringC";
  System.out.println("//tagname[text()='" +str1+ "']/tagname[text()='" +str2+ "']/tagname[text()='" +str3+ "']");
  

• Console output:

  //tagname[text()='stringA']/tagname[text()='stringB']/tagname[text()='stringC']
  

Suppose xpath is "//tagname[text()='param']/tagname[text()='param']/tagname[text()='param']" and param is pattern that need to be replaced.

public static String replaceValue(String xpath , String...params){
	for(String replacement : params){
		xpath = xpath.replaceFirst("param",replacement);
	}
	return xpath;
}

you also can use a regex pattern instead of 'param' keyword in xpath.