问题

在我的Android应用程序中，我有两个浮点数组，我想要计算它们之间的距离：

float[] arrayA;
float[] arrayB;
diff = ?

在Python中，我这样做：

diff = np.sum(abs(arrayA - arrayB))

我找不到Java中相同的运算符。

我应该使用for循环吗？或者有更快的方法吗？

英文:

Insime my Android app, I have two float arrays and I want to compute the distance:

float[] arrayA;
float[] arrayB;
diff = ?

In Python I do:

diff = np.sum(abs(arrayA - arrayB))

I can't find the same operators in java.

Should I use a for loop? Or there are faster ways?

答案1

得分: 1

尝试这段代码，如果你想对每个元素都进行操作：

float[] diff = new float[arrayA.length];//假设长度相同
for (int i = 0; i < diff.length; i++) {
   diff[i] = arrayA[i] - arrayB[i];
}

或者，如果你只想要一个变量作为结果：

float diff = 0;
for (int i = 0; i < diff.length; i++) {
   diff += arrayA[i] - arrayB[i];
}

英文:

Try this code if you want to have it for each element:

float[] diff=new float[arrayA.length];//Assuming same length
for(int i=0;i&lt;diff.length;i++){
   diff[i]=arrayA[i]-arrayB[i];
}

Or, if you only want one variable as result:

float[] diff=0;
for(int i=0;i&lt;diff.length;i++){
   diff+=arrayA[i]-arrayB[i];
}

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