英文:
Split string using multiple patterns, where second pattern matches smaller parts of the first
问题
Here's the translated code snippet:
for (String substr : "§x§7§3§7§5§f§f§ltest1 §rtest2".split("((?<=(§x(§[0-9a-f]){6}))|(?<=§[0-9a-z])|(?=§[0-9a-z]))")) {
System.out.println(substr);
}
Please note that the code itself remains in English since code keywords and syntax are typically written in English regardless of the programming language used.
英文:
I'm reading special "formatting codes" in a string and am trying to split the string so that I have those formatting codes and the string's text separated.
There are two "types" of formatting codes: "Encoded" hex colors: §x§7§3§7§5§f§f and other codes in the format of §r.
Given the example string: §x§7§3§7§5§f§f§ltest1 §rtest2
I need the larger pattern split as a whole, and then the smaller ones. I can do what I want on those patterns separately, but am having trouble combining them into a single regex. Because the second pattern matches pieces of the first pattern, it's just splitting everything into smaller groups.
I'm trying this:
for (String substr : "§x§7§3§7§5§f§f§ltest1 §rtest2".split("((?<=(§x(§[0-9a-f]){6}))|(?<=§[0-9a-z])|(?=§[0-9a-z]))")) {
System.out.println(substr);
}
My expected output is:
§x§7§3§7§5§f§f
§l
test1
§r
test
My actual output is:
§x
§7
§3
§7
§5
§f
§f
§l
test1
§r
test2
When I split the expressions up into different split tests, they work, they're just not working together.
答案1
得分: 2
Instead of splitting, you could just use this simplified regex for matching:
§x(?:§[0-9a-f]){6}|§[0-9a-z]|[^§\s]+
RegEx Details:
§x(?:§[0-9a-f]){6}: 匹配以§x开头的文本，后面跟着 6 个十六进制字符|: 或§[0-9a-z]: 匹配以§开头的文本，后面跟着一个字母数字字符|: 或[^§\s]+: 匹配 1 个或多个非空格且非§字符
Code:
final String regex = ""§x(?:§[0-9a-f]){6}|§[0-9a-z]|[^§\\s]+"";
final String string = ""§x§7§3§7§5§f§f§ltest1 §rtest2"";
final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
System.out.println(matcher.group(0));
}
英文:
Instead of splitting, you could just use this simplified regex for matching:
§x(?:§[0-9a-f]){6}|§[0-9a-z]|[^§\s]+
RegEx Details:
§x(?:§[0-9a-f]){6}: Match text starting with§xand 6 hex characters|: OR§[0-9a-z]: Match text starting with§and an alphanumeric|: OR[^§\s]+: Match 1+ non-whitespace and non-§characters
Code:
final String regex = "§x(?:§[0-9a-f]){6}|§[0-9a-z]|[^§\\s]+";
final String string = "§x§7§3§7§5§f§f§ltest1 §rtest2";
final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
System.out.println( matcher.group(0) );
}
答案2
得分: 1
你可以使用以下正则表达式：
?((?:§[^§])(?=[^§])|[^§ ]{2,})
它的工作原理如下：
?可选地匹配空格字符。((?:§[^§])(?=[^§])|[^§ ]{2,})捕获以下之一：(?:§[^§])(?=[^§])匹配以下内容：(?:§[^§])匹配§后跟任何字符，但不包括§。(?=[^§])前瞻，确保接下来的字符不是§（与(?!§)相同，但更高效）。
[^§ ]{2,}匹配任何字符，除了§或空格，两次或更多。
通过替换为 \n$1
结果：
§x§7§3§7§5§f§f
§l
test1
§r
test2
英文:
You can use the following regex:
?((?:§[^§])(?=[^§])|[^§ ]{2,})
How it works:
?optionally match the space character((?:§[^§])(?=[^§])|[^§ ]{2,})capture either of the following:(?:§[^§])(?=[^§])match the following:(?:§[^§])match§followed by any character except§(?=[^§])lookahead ensuring what follows is not§(same as(?!§)but more efficient)
[^§ ]{2,}match any character except§or space two or more times
With the substitution of \n$1
Result:
§x§7§3§7§5§f§f
§l
test1
§r
test2
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