error: 不兼容的类型：String[] 无法转换为String

huangapple
go评论101阅读模式
英文:

error: incompatible types: String[] cannot be converted to String

问题

以下是您代码的翻译部分：

  1. 我尝试在Java中使用字符串拆分函数接受一个6x6的矩阵输入，输入方式如下，并打印该矩阵。
  3. 1 2 3 4 5 6
  4. 1 2 3 4 5 6
  5. 1 2 3 4 5 6
  6. 1 2 3 4 5 6
  7. 1 2 3 4 5 6
  8. 1 2 3 4 5 6
  10. 我得到的输出是：
  12. Main.java:24: 错误：不兼容的类型：String[]无法转换为String
  13. c[j] = b[i].split(" ");
  15. 我的代码：
  17. import java.util.*;
  18. import java.io.*;
  20. class Solution {
  21.     public static void main(String args[]) {
  22.         Scanner s = new Scanner(System.in);
  23.         int a[][] = new int[6][6];
  24.         String b[] = new String[6];
  26.         for (int i = 0; i < 6; i++) {
  27.             b[i] = s.nextLine();
  28.         }
  30.         // 初始化二维数组a[][]
  31.         for (int i = 0; i < 6; i++) {
  32.             for (int j = 0; j < 6; j++) {
  33.                 String c[] = new String[6];
  34.                 c[j] = b[i].split(" ");
  35.                 a[i][j] = Integer.parseInt(c[j]);
  36.             }
  37.         }
  39.         // 打印输入数组
  40.         for (int i = 0; i < 6; i++) {
  41.             for (int j = 0; j < 6; j++) {
  42.                 System.out.print("\ta[i][j]\t");
  43.             }
  44.         }
  45.     }
  46. }
  47. 请建议我如何克服这个错误

希望这有助于您理解并解决代码中的问题。如果您需要进一步的帮助，请随时提出。

英文:

I tried taking input of a 6 by 6 matrix in java using the string split function when the string is input in the following way, and to print the matrix.

  1. 1 2 3 4 5 6
  2. 1 2 3 4 5 6
  3. 1 2 3 4 5 6
  4. 1 2 3 4 5 6
  5. 1 2 3 4 5 6
  6. 1 2 3 4 5 6

The output that I get is

  1. Main.java:24: error: incompatible types: String[] cannot be converted to String
  2. c[j] = b[i].split(" ");

my code:

  1. import java.util.*;
  2. import java.io.*;
  4. class Solution {
  5.     public static void main(String args[]) {
  6.         Scanner s = new Scanner(System.in);
  7.         int a[][] = new int[6][6];
  8.         String b[] = new String[6];
  10.         for (int i = 0; i < 6; i++) {
  11.             b[i] = s.nextLine();
  12.         }
  14.         // initializing the 2d array a[][]
  15.         for (int i = 0; i < 6; i++) {
  16.             for (int j = 0; j < 6; j++) {
  17.                 String c[] = new String[6];
  18.                 c[j] = b[i].split(" ");
  19.                 a[i][j] = Integer.parseInt(c[j]);
  20.             }
  21.         }
  23.         // printing the input array
  24.         for (int i = 0; i < 6; i++) {
  25.             for (int j = 0; j < 6; j++) {
  26.                 System.out.print("\ta[i][j]\t");
  27.             }
  28.         }
  29.     }
  30. }

pls, suggest how I can overcome this error

答案1

得分: 0

split()函数的返回类型是数组类型。因为您要求Java将每个由" "（空格）分隔的值作为单独的值提供给您。所以Java将创建每个值的数组并返回给您。要存储数组，您需要一个数组类型的变量。在这里，c代表一个数组，但c[j]表示数组的单个索引。

您可以像这样更改您的代码：

  1. for (int i = 0; i < 6; i++) {
  2.     String c[] = b[i].split(" ");
  3.     for (int k = 0; k < c.length; k++) {
  4.         a[i][k] = Integer.parseInt(c[k]);
  5.     }
  6. }

输入是整数，您稍后将它们转换为整数，我建议您将输入直接作为整数接收，如下所示：

  1. class Solution {
  2.     public static void main(String args[]) {
  3.         Scanner s = new Scanner(System.in);
  4.         int a[][] = new int[6][6];
  6.         for (int i = 0; i < 6; i++) {
  7.             for (int j = 0; j < 6; j++) {
  8.                 a[i][j] = s.nextInt();
  9.             }
  10.         }
  12.         // 打印输入数组
  13.         for (int i = 0; i < 6; i++) {
  14.             for (int j = 0; j < 6; j++) {
  15.                 System.out.print("\ta[i][j]\t");
  16.             }
  17.         }
  18.     }
  19. }
英文:

The return type of split() function is type of array. Because you are asking java to give me each value as separate which is separated by " " (space). So java will create an array of each value and returns you the array. For storing the array you need an variable of type array. here c represent an array, but c[j] represents an single index of the array.

You can change your code like:

  1. for (int i = 0; i < 6; i++) {
  2.     String c[] = b[i].split(" ");
  3.     for (int k = 0; k < c.length; k++) {
  4.         a[i][k] = Integer.parseInt(c[k]);
  5.     }
  6. }

The the inputs are integer and you are converting them to integer later, I would suggest you to take input as integer like below:

  1. class Solution {
  2.     public static void main(String args[]) {
  3.         Scanner s = new Scanner(System.in);
  4.         int a[][] = new int[6][6];
  6.         for (int i = 0; i < 6; i++) {
  7.             for (int j = 0; j < 6; j++) {
  8.                 a[i][j] = s.nextInt();
  9.             }
  10.         }
  12.         // printing the input array
  13.         for (int i = 0; i < 6; i++) {
  14.             for (int j = 0; j < 6; j++) {
  15.                 System.out.print("\ta[i][j]\t");
  16.             }
  17.         }
  18.     }
  19. }

答案2

得分: 0

当我们调用String的split函数时，返回的是String[]。因此，类型为String的c[j]不能等于String[]。

下面的代码应该替换为：

  1. // 初始化2D数组a[][]
  2. for (int i = 0; i < 6; i++) {
  3.     String[] c = b[i].split(" ");
  4.     for (int j = 0; j < 6; j++) {
  5.         a[i][j] = Integer.parseInt(c[j]);
  6.     }
  7. }
英文:

When we call split function of String return the String[]. So c[j] (which is of type String) can't be equal to String[].

Below code should be replaced as:

  1. // initializing the 2d array a[][]
  2. for (int i = 0; i &lt; 6; i++) {
  3.     String[] c = b[i].split(&quot; &quot;);
  4.     for (int j = 0; j &lt; 6; j++) {
  5.         a[i][j] = Integer.parseInt(c[j]);
  6.     }
  7. }

huangapple
  • 本文由 发表于 2020年8月10日 12:01:40
  • 转载请务必保留本文链接：https://go.coder-hub.com/63333986.html
  • java
  • multidimensional-array
  • split
  • string-formatting
  • tostring
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定