英文:
error: incompatible types: String[] cannot be converted to String
问题
以下是您代码的翻译部分：
我尝试在Java中使用字符串拆分函数接受一个6x6的矩阵输入，输入方式如下，并打印该矩阵。
1 2 3 4 5 6
1 2 3 4 5 6
1 2 3 4 5 6
1 2 3 4 5 6
1 2 3 4 5 6
1 2 3 4 5 6
我得到的输出是：
Main.java:24: 错误：不兼容的类型：String[]无法转换为String
c[j] = b[i].split(" ");
我的代码：
import java.util.*;
import java.io.*;
class Solution {
public static void main(String args[]) {
Scanner s = new Scanner(System.in);
int a[][] = new int[6][6];
String b[] = new String[6];
for (int i = 0; i < 6; i++) {
b[i] = s.nextLine();
}
// 初始化二维数组a[][]
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 6; j++) {
String c[] = new String[6];
c[j] = b[i].split(" ");
a[i][j] = Integer.parseInt(c[j]);
}
}
// 打印输入数组
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 6; j++) {
System.out.print("\ta[i][j]\t");
}
}
}
}
请建议我如何克服这个错误
希望这有助于您理解并解决代码中的问题。如果您需要进一步的帮助，请随时提出。
英文:
I tried taking input of a 6 by 6 matrix in java using the string split function when the string is input in the following way, and to print the matrix.
1 2 3 4 5 6
1 2 3 4 5 6
1 2 3 4 5 6
1 2 3 4 5 6
1 2 3 4 5 6
1 2 3 4 5 6
The output that I get is
Main.java:24: error: incompatible types: String[] cannot be converted to String
c[j] = b[i].split(" ");
my code:
import java.util.*;
import java.io.*;
class Solution {
public static void main(String args[]) {
Scanner s = new Scanner(System.in);
int a[][] = new int[6][6];
String b[] = new String[6];
for (int i = 0; i < 6; i++) {
b[i] = s.nextLine();
}
// initializing the 2d array a[][]
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 6; j++) {
String c[] = new String[6];
c[j] = b[i].split(" ");
a[i][j] = Integer.parseInt(c[j]);
}
}
// printing the input array
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 6; j++) {
System.out.print("\ta[i][j]\t");
}
}
}
}
pls, suggest how I can overcome this error
答案1
得分: 0
split()函数的返回类型是数组类型。因为您要求Java将每个由" "（空格）分隔的值作为单独的值提供给您。所以Java将创建每个值的数组并返回给您。要存储数组，您需要一个数组类型的变量。在这里，c代表一个数组，但c[j]表示数组的单个索引。
您可以像这样更改您的代码：
for (int i = 0; i < 6; i++) {
String c[] = b[i].split(" ");
for (int k = 0; k < c.length; k++) {
a[i][k] = Integer.parseInt(c[k]);
}
}
输入是整数，您稍后将它们转换为整数，我建议您将输入直接作为整数接收，如下所示：
class Solution {
public static void main(String args[]) {
Scanner s = new Scanner(System.in);
int a[][] = new int[6][6];
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 6; j++) {
a[i][j] = s.nextInt();
}
}
// 打印输入数组
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 6; j++) {
System.out.print("\ta[i][j]\t");
}
}
}
}
英文:
The return type of split() function is type of array. Because you are asking java to give me each value as separate which is separated by " " (space). So java will create an array of each value and returns you the array. For storing the array you need an variable of type array. here c represent an array, but c[j] represents an single index of the array.
You can change your code like:
for (int i = 0; i < 6; i++) {
String c[] = b[i].split(" ");
for (int k = 0; k < c.length; k++) {
a[i][k] = Integer.parseInt(c[k]);
}
}
The the inputs are integer and you are converting them to integer later, I would suggest you to take input as integer like below:
class Solution {
public static void main(String args[]) {
Scanner s = new Scanner(System.in);
int a[][] = new int[6][6];
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 6; j++) {
a[i][j] = s.nextInt();
}
}
// printing the input array
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 6; j++) {
System.out.print("\ta[i][j]\t");
}
}
}
}
答案2
得分: 0
当我们调用String的split函数时，返回的是String[]。因此，类型为String的c[j]不能等于String[]。
下面的代码应该替换为：
// 初始化2D数组a[][]
for (int i = 0; i < 6; i++) {
String[] c = b[i].split(" ");
for (int j = 0; j < 6; j++) {
a[i][j] = Integer.parseInt(c[j]);
}
}
英文:
When we call split function of String return the String[]. So c[j] (which is of type String) can't be equal to String[].
Below code should be replaced as:
// initializing the 2d array a[][]
for (int i = 0; i < 6; i++) {
String[] c = b[i].split(" ");
for (int j = 0; j < 6; j++) {
a[i][j] = Integer.parseInt(c[j]);
}
}
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